Oracle SQL 如何使用多个连接和 groupby 编写复杂的查询

Question

Oracle SQL：我有以下一组查询，全部从同一个表中获取。 我想知道是否有办法将所有内容合并为一个查询？

SELECT COUNT(T.ISSUE_NUMBER) total_cases,
       COUNT(CASE WHEN T.DIST_COMPLETED_STATUS = 'Closed' THEN 1 END) total_close,
       COUNT(CASE WHEN T.DIST_COMPLETED_STATUS = 'Open' THEN 1 END) total_open,
       COUNT(CASE WHEN T.IS_DUPLICATE = 1 THEN 1 END) total_duplicate,
       COUNT(CASE WHEN T.IS_REJECTION = 1 THEN 1 END) total_rejected,
       T.G_SECTOR 
FROM TRANSFORMED T
WHERE T.SERVICE_CENTER_ENGLISH = 'Center' 
AND TO_DATE(T.RAISED_ON)  >= TRUNC(SYSDATE)-30
AND T.IS_DISTORTION = 1
GROUP BY T.G_SECTOR 
ORDER BY 1 DESC

SELECT COUNT(T.ISSUE_NUMBER) total_cases,
       COUNT(CASE WHEN T.DIST_COMPLETED_STATUS = 'Closed' THEN 1 END) total_close,
       COUNT(CASE WHEN T.DIST_COMPLETED_STATUS = 'Open' THEN 1 END) total_open,
       COUNT(CASE WHEN T.IS_DUPLICATE = 1 THEN 1 END) total_duplicate,
       COUNT(CASE WHEN T.IS_REJECTION = 1 THEN 1 END) total_rejected,
       T.AGENCY_NAME,T.DIST_AGENCY_TYPE
FROM TRANSFORMED T
WHERE T.SERVICE_CENTER_ENGLISH = 'Center' 
AND TO_DATE(T.RAISED_ON)  >= TRUNC(SYSDATE)-30
AND T.IS_DISTORTION = 1
GROUP BY T.AGENCY_NAME, T.DIST_AGENCY_TYPE
ORDER BY 1 DESC

SELECT COUNT(T.ISSUE_NUMBER) total_cases,
       COUNT(CASE WHEN T.DIST_COMPLETED_STATUS = 'Closed' THEN 1 END) total_close,
       COUNT(CASE WHEN T.DIST_COMPLETED_STATUS = 'Open' THEN 1 END) total_open,
       COUNT(CASE WHEN T.IS_DUPLICATE = 1 THEN 1 END) total_duplicate,
       COUNT(CASE WHEN T.IS_REJECTION = 1 THEN 1 END) total_rejected,
       T.VIOLATION_ENGLISH,T.DIST_AGENCY_TYPE
FROM TRANSFORMED T
WHERE T.SERVICE_CENTER_ENGLISH = 'Center' 
AND TO_DATE(T.RAISED_ON)  >= TRUNC(SYSDATE)-30
AND T.IS_DISTORTION = 1
GROUP BY T.VIOLATION_ENGLISH, T.DIST_AGENCY_TYPE
ORDER BY 1 DESC

Answer 1

SELECT *
FROM (
SELECT COUNT(T.ISSUE_NUMBER) total_cases,
       COUNT(CASE WHEN T.DIST_COMPLETED_STATUS = 'Closed' THEN 1 END) total_close,
       COUNT(CASE WHEN T.DIST_COMPLETED_STATUS = 'Open' THEN 1 END) total_open,
       COUNT(CASE WHEN T.IS_DUPLICATE = 1 THEN 1 END) total_duplicate,
       COUNT(CASE WHEN T.IS_REJECTION = 1 THEN 1 END) total_rejected,
       T.G_SECTOR, '' AS AGENCY_NAME, '' AS VIOLATION_ENGLISH, '' AS DIST_AGENCY_TYPE 
FROM TRANSFORMED T
WHERE T.SERVICE_CENTER_ENGLISH = 'Center' 
AND TO_DATE(T.RAISED_ON)  >= TRUNC(SYSDATE)-30
AND T.IS_DISTORTION = 1
GROUP BY T.G_SECTOR 

UNION ALL    
SELECT COUNT(T.ISSUE_NUMBER) total_cases,
       COUNT(CASE WHEN T.DIST_COMPLETED_STATUS = 'Closed' THEN 1 END) total_close,
       COUNT(CASE WHEN T.DIST_COMPLETED_STATUS = 'Open' THEN 1 END) total_open,
       COUNT(CASE WHEN T.IS_DUPLICATE = 1 THEN 1 END) total_duplicate,
       COUNT(CASE WHEN T.IS_REJECTION = 1 THEN 1 END) total_rejected,
       '' AS G_SECTOR, T.AGENCY_NAME, '' AS VIOLATION_ENGLISH, T.DIST_AGENCY_TYPE
FROM TRANSFORMED T
WHERE T.SERVICE_CENTER_ENGLISH = 'Center' 
AND TO_DATE(T.RAISED_ON)  >= TRUNC(SYSDATE)-30
AND T.IS_DISTORTION = 1
GROUP BY T.AGENCY_NAME, T.DIST_AGENCY_TYPE

UNION ALL    
SELECT COUNT(T.ISSUE_NUMBER) total_cases,
       COUNT(CASE WHEN T.DIST_COMPLETED_STATUS = 'Closed' THEN 1 END) total_close,
       COUNT(CASE WHEN T.DIST_COMPLETED_STATUS = 'Open' THEN 1 END) total_open,
       COUNT(CASE WHEN T.IS_DUPLICATE = 1 THEN 1 END) total_duplicate,
       COUNT(CASE WHEN T.IS_REJECTION = 1 THEN 1 END) total_rejected,
       '' AS G_SECTOR, '' AS AGENCY_NAME, T.VIOLATION_ENGLISH,T.DIST_AGENCY_TYPE
FROM TRANSFORMED T
WHERE T.SERVICE_CENTER_ENGLISH = 'Center' 
AND TO_DATE(T.RAISED_ON)  >= TRUNC(SYSDATE)-30
AND T.IS_DISTORTION = 1
GROUP BY T.VIOLATION_ENGLISH, T.DIST_AGENCY_TYPE
) A
ORDER BY 1 DESC

Answer 2

是的，Oracle 具有用于分组数据的高级机制： ROLLUP、CUBE、GROUPING Functions 和 GROUPING SETS 。 在您的情况下，分组集似乎很有希望。

这是我的表：

create table t(a, b, c, d, e, f) as (
    select 'A1', 'B1', 'C1', 'D1', 'E1', 701 from dual union all
    select 'A2', 'B1', 'C2', 'D1', 'E2', 702 from dual union all
    select 'A2', 'B1', 'C2', 'D1', 'E3', 703 from dual );

您的查询仅在group by部分group by有所不同，并且您自然会选择作为组基础的不同列。 where条件和条件计数并不重要。 您的选择看起来像：

 select a, count(1) from t group by a;

 select b, c, count(1) from t group by b, c;

 select d, e, count(1) from t group by d, e;

你可以这样做：

select a, b, c, d, e, grouping_id(a, b, c, d, e) grp_id, count(1) cnt 
  from t 
  group by grouping sets( (a, null), (b, c), (d, e) )

输出：

A  B  C  D  E      GRP_ID        CNT
-- -- -- -- -- ---------- ----------
A1                     15          1
A2                     15          2
   B1 C1               19          1
   B1 C2               19          2
         D1 E1         28          1
         D1 E2         28          1
         D1 E3         28          1

Answer 3

GROUPING SETS应该做你想做的：

SELECT T.G_SECTOR, T.AGENCY_NAME, T.DIST_AGENCY_TYPE,
       T.VIOLATION_ENGLISH, T.DIST_AGENCY_TYPE,
       COUNT(T.ISSUE_NUMBER) as total_cases,
       COUNT(CASE WHEN T.DIST_COMPLETED_STATUS = 'Closed' THEN 1 END) as total_close,
       COUNT(CASE WHEN T.DIST_COMPLETED_STATUS = 'Open' THEN 1 END) as total_open,
       COUNT(CASE WHEN T.IS_DUPLICATE = 1 THEN 1 END) as total_duplicate,
       COUNT(CASE WHEN T.IS_REJECTION = 1 THEN 1 END) as total_rejected
FROM TRANSFORMED T
WHERE T.SERVICE_CENTER_ENGLISH = 'Center' AND
      TO_DATE(T.RAISED_ON)  >= TRUNC(SYSDATE)-30 AND
      T.IS_DISTORTION = 1
GROUP BY GROUPING SETS ( (T.G_SECTOR), 
                         (T.AGENCY_NAME, T.DIST_AGENCY_TYPE),
                         (T.VIOLATION_ENGLISH, T.DIST_AGENCY_TYPE)
                       )
ORDER BY total_cases DESC;