[英]How to get the sum of a subquery that returns sums?
我想在以下情况下获得“总和”的总和。 我怎样才能做到这一点? 下图代表了我执行下面的代码后得到的表格。 我只想收到 2 条记录,它们是:
或 Gazit | 052-3322445 | 36400
丹盖 | 050-3023322 | 12000
SELECT Distinct(o1.FirstName & " " & o1.LastName) as [Full Name], o1.PhoneStart & "-" &
o1.PhoneNumber as [Phone Number],
(SELECT SUM(OrderProducts.ClientPrice*OrderProducts.Quantity) FROM OrderProducts WHERE
OrderProducts.Order = o2.ID AND o2.Client = o1.ID) AS [Order Price]
FROM Clients as o1 INNER JOIN (Orders as o2 INNER JOIN OrderProducts as o3 ON o2.ID =
o3.Order) ON o1.ID = o2.Client
ORDER BY 3 DESC;
谢谢。
要么我误解了您的要求,要么您将其复杂化。 似乎您只需要使用 group by 子句进行一些聚合(即总和)。 这对你有用吗?
select o1.FirstName & " " & o1.LastName as [Full Name]
, o1.PhoneStart & "-" & o1.PhoneNumber as [Phone Number]
, sum(o3.ClientPrice * o3.Quantity) as [Order Price]
from Clients o1
inner join Orders o2 on o1.ID = o2.Client
inner join OrderProducts o3 on o2.ID = o3.Order
group by o1.FirstName
, o1.LastName
, o1.PhoneStart
, o1.PhoneNumber
order by 3 desc
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