如何从数组中获取元素

Question

我有一个数组，它是

myArr = [ { "root": ["1", "6"], "element": "Apple" }, { "root": ["2", "7"], "element": "Banana" }, { "root": ["3", "8"], "element": "Orange" }, { "root": ["4", "9"], "element": "WaterMelon" }, { "root": ["5"], "element": "Kiwi" } ]

只是想知道我是否有一个与上面的根数组之一匹配的 '3' 字符串，我想从上面的数组中获取元素，我应该如何在 javascript 中做到这一点？ 有什么帮助吗？ 谢谢

Answer 1

你可以这样过滤你的数组+ destructing你的根以检查它是否包含“3”：

 const s = "3" const myArr = [{ "root": ["1", "6"], "element": "Apple" }, { "root": ["2", "7"], "element": "Banana" }, { "root": ["3", "8"], "element": "Orange" }, { "root": ["4", "9"], "element": "WaterMelon" }, { "root": ["5"], "element": "Kiwi" }]; const res = myArr.filter(({ root }) => root.includes(s)) console.log(res)

Answer 2

只需过滤数组即可获取元素：

 const myArr = [ { "root": ["1", "6"], "element": "Apple" }, { "root": ["2", "7"], "element": "Banana" }, { "root": ["3", "8"], "element": "Orange" }, { "root": ["4", "9"], "element": "WaterMelon" }, { "root": ["5"], "element": "Kiwi" } ]; const ele = myArr.filter(arr => arr.root.includes("3")); console.log("Required", ele);

Answer 3

我希望这能让你开始：

myArr.forEach((x)=>{ 
    x.root.forEach((j)=> { 
        if(j=='3'){console.log( x.element);}
    })
})

迭代主数组，然后为每个元素迭代“根”数组。 如果匹配'3'，则返回主项的元素字段

Answer 4

const myArr = [
  {
    root: ["1", "6"],
    element: "Apple"
  },
  {
    root: ["2", "7"],
    element: "Banana"
  },
  {
    root: ["3", "8"],
    element: "Orange"
  },
  {
    root: ["4", "9"],
    element: "WaterMelon"
  },
  {
    root: ["5"],
    element: "Kiwi"
  }
];

const stringToFind = "3";

const elemList = myArr
  .filter(obj => obj.root.includes(stringToFind))
  .map(obj => obj.element);

console.log(elemList);