groovy：将字符串（列表）转换为 Groovy 列表

Question

import groovy.json.JsonSlurper

def ver = "['a', 'b', 'c']"
def jsonSlurper = new JsonSlurper()
def ver_list = jsonSlurper.parseText(ver)
println ver_list

这就是我正在做的。 我想遍历ver_list 。 而且似乎很难找到解决方案。

这是我打印 ver_list 时的错误：

Caught: groovy.json.JsonException: Unable to determine the current character, it is not a string, number, array, or object

The current character read is ''' with an int value of 39
Unable to determine the current character, it is not a string, number, array, or object
line number 1
index number 1
['a', 'b', 'c']
.^
groovy.json.JsonException: Unable to determine the current character, it is not a string, number, array, or object

The current character read is ''' with an int value of 39
Unable to determine the current character, it is not a string, number, array, or object
line number 1
index number 1
['a', 'b', 'c']

Answer 1

有效的 json 字符串必须用双引号引起来。

所以改变你的代码这一行，它应该可以工作：

def ver = '["a", "b", "c"]'

但是，如果您需要解析无效的 json，您可以尝试 LAX 解析器。

然后甚至可以解析以下字符串

import groovy.json.JsonSlurper
import groovy.json.JsonParserType

def ver = "[a, 'b', 001]"
def jsonSlurper = new JsonSlurper().setType( JsonParserType.LAX )
def ver_list = jsonSlurper.parseText(ver)
println ver_list