列存在但迁移时它返回 SQLSTATE[42000]：语法错误或访问冲突：1072 表中不存在键列

Question

列存在但迁移时返回

SQLSTATE[42000]：语法错误或访问冲突：1072 表中不存在键列

当我删除外键时，问题就解决了

  public function up()
{
    Schema::create('users', function (Blueprint $table) {
        $table->increments('id');
        $table->string('name');
        $table->string('email')->unique();
        $table->timestamp('email_verified_at')->nullable();
        $table->string('password');
        $table->rememberToken();
        $table->timestamps();
    });
}

   public function up()
{
    Schema::create('skills', function (Blueprint $table) {
        $table->increments('id');
        $table->string('skill_name')->nullable();
        $table->decimal('skill_note')->nullable();           
        $table->timestamps();
    });
}


   public function up()
    {
        Schema::create('skill_user', function (Blueprint $table) {
            $table->increments('id');
            $table->unsignedInteger('user_id');
            $table->foreign('user_id ')
                ->references('id')->on('users');
            $table->unsignedInteger('skill_id');
            $table->foreign('skill_id')
                ->references('id')->on('skills');
            $table->decimal('note')->nullable();
            $table->timestamps();
        });
    }

Answer 1

在第 6 版（您用于我在评论中读到的内容的那个）中， increments('id') 方法不会创建无符号整数，而是创建一个无符号大整数，因此您需要更改您的外键

$table->unsignedBigInteger('user_id');
$table->unsignedBigInteger('skill_id');

Answer 2

试试这个。

 $table->integer('user_id')->unsigned(); $table->integer('skill_id')->unsigned();

如果它不起作用，我建议运行 composer install 和 migrate:fresh