[英]Java Generics: Subclassing a generic superclass - is subclass a reifiable type?
[英]Subclassing a subclass of a (generic) builder
我正在尝试使用多级 inheritance 实现构建器 object。 我从Subclassing a Java Builder class中获得了一些灵感,这是我的(简化的)代码:
public class StackOverflow {
public static class Builder<T extends Builder<T>> {
public Builder() {}
public T doA() {
System.out.println("A");
return (T) this;
}
}
public static class BuilderSubclass <T extends BuilderSubclass<T>>
extends Builder<BuilderSubclass<T>> {
public BuilderSubclass() {}
public T doB() {
System.out.println("B");
return (T) this;
}
}
public static class BuilderSubclassSubclass
extends BuilderSubclass<BuilderSubclassSubclass> {
public BuilderSubclassSubclass() {}
public BuilderSubclassSubclass doC() {
System.out.println("C");
return this;
}
}
}
我想做这样的事情: new StackOverflow.BuilderSubclassSubclass().doA().doC().doB()
但是,当我调用new StackOverflow.BuilderSubclassSubclass().doA()
时,返回的 object 不是BuilderSubclassSubclass
而是BuilderSubclass<BuilderSubclassSubclass>
。 我知道为什么会这样: Builder
的泛型类型是BuilderSubclass<BuilderSubclassSubclass>
,它在 BuilderSubclass 的BuilderSubclass
签名中分配。
关于如何避免这个问题的任何想法?
更新:我想我可以避免使用构建器模式,而是像这样调用函数:
StackOverflow.BuilderSubclassSubclass builder = new StackOverflow.BuilderSubclassSubclass();
builder.doA();
builder.doB();
builder.doC();
在这种情况下,代码变为:
public class StackOverflowBatchHelperFunctions {
public static class Builder {
public Builder() {
}
public void doA() {
System.out.println("A");
}
}
public static class BuilderSubclass extends Builder {
public BuilderSubclass() {
super();
}
public void doB() {
System.out.println("B");
}
}
public static class BuilderSubclassSubclass extends BuilderSubclass {
public BuilderSubclassSubclass() {
super();
}
public void doC() {
System.out.println("C");
}
}
}
但是我认为这不那么“漂亮”,所以我仍然希望看到最初问题的答案。
You should replace public static class BuilderSubclass<T extends BuilderSubclass<T>> extends Builder<BuilderSubclass<T>>
with public static class BuilderSubclass<T extends BuilderSubclass<T>> extends Builder<T>
.
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