[英]How to calculate the difference of two SELECTs in SQL (Access, JetSQL)
我需要从同一个表连接中获取两个SUM...WHERE
查询的区别:
SELECT SUM(Service_template.Service_fee)
FROM (Service_template LEFT JOIN Service ON Service_template.Service_Code = Service.Service_Code) LEFT JOIN Bill ON Service.Service_ID = Bill.Service_ID
WHERE Bill.Service_ID IS NOT NULL
和
SELECT SUM(Service_template.Service_fee)
FROM (Service_template LEFT JOIN Service ON Service_template.Service_Code = Service.Service_Code) LEFT JOIN Bill ON Service.Service_ID = Bill.Service_ID
我试过使用UNION
,但它返回两行,而不是我可以进行计算的两列。
我该怎么做go呢? 我觉得我错过了一些微不足道的东西,所以提前谢谢!
这应该有效:
Select
Sum(T1.Sum1),
Sum(T2.Sum2),
Sum(T1.Sum1) - Sum(T2.Sum2) As Diff1,
Sum(T2.Sum2) - Sum(T1.Sum1) As Diff2
From
(SELECT SUM(Service_template.Service_fee) As Sum1 FROM (Service_template LEFT JOIN Service ON Service_template.Service_Code = Service.Service_Code) LEFT JOIN Bill ON Service.Service_ID = Bill.Service_ID WHERE Bill.Service_ID IS NOT NULL) As T1,
(SELECT SUM(Service_template.Service_fee) As Sum2 FROM (Service_template LEFT JOIN Service ON Service_template.Service_Code = Service.Service_Code) LEFT JOIN Bill ON Service.Service_ID = Bill.Service_ID) As T2
如果你想要所有三个值,你可以使用条件聚合:
SELECT SUM(IIF(b.Service_ID IS NOT NULL, st.Service_fee, 0)) as total_1,
SUM(b.Service_Id) as total_2,
SUM(IIF(b.Service_ID IS NULL, st.Service_fee, 0)) as diff
FROM (Service_template as st LEFT JOIN
Service as s
ON st.Service_Code = s.Service_Code
) LEFT JOIN
Bill as b
ON s.Service_ID = b.Service_ID;
如果您只想要Service_Id
为NULL
的SUM()
,那么:
SELECT SUM(b.Service_Id) as diff
FROM (Service_template as st LEFT JOIN
Service as s
ON st.Service_Code = s.Service_Code
) LEFT JOIN
Bill as b
ON s.Service_ID = b.Service_ID
WHERE b.Service_ID IS NULL;
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