如何从 Autofac Registrations 中获取用于注册的类型

Question

如何从container.ComponentRegistry.Registrations获取用于在容器中注册 class 的类型？

    // I have some types like

    interface IBase { }
    interface IA : IBase { }
    interface IB : IBase { }

    class A : IA { }
    class B : IB { }

    class Program
    {
        static void Main(string[] args)
        {
            var builder = new ContainerBuilder();

            // Registering types as interface implementations
            builder.RegisterType<A>().As<IA>();
            builder.RegisterType<B>().As<IB>();

            var c = builder.Build();


            // Trying to get all registered types assignable to IBase
            var types = c.ComponentRegistry.Registrations
                .Where(r => typeof(IBase).IsAssignableFrom(r.Activator.LimitType))
                .Select(r => r.Activator.LimitType); // Returns A insted of IA

            // Trying to Resolve all types
            types.Select(t => c.Resolve(t) as IBase).ToList();
        }
    }

因为.Activator.LimitType返回容器中使用的IA类型A类型，所以我得到一个异常

Autofac.Core.Registration.ComponentNotRegisteredException: The requested service 'A' has not been registered. To avoid this exception, either register a component to provide the service, check for service registration using IsRegistered(), or use the ResolveOptional() method to resolve an optional dependency.

Answer 1

一种方法是确保您的寄存器A不仅针对IA ，而且针对IBase （对于B也是如此）。

然后解析IEnumerable<IBase>将找到A和B ：

using System;
using System.Collections.Generic;
using System.Linq;
using Autofac;

namespace WatCode
{
    interface IBase { }
    interface IA : IBase { }
    interface IB : IBase { }

    class A : IA { }
    class B : IB { }

    class Program
    {
        static void Main(string[] args)
        {
            var builder = new ContainerBuilder();

            // Registering types as interface implementations
            builder.RegisterType<A>().AsImplementedInterfaces(); // register against IA and IBase
            builder.RegisterType<B>().AsImplementedInterfaces(); // register against IB and IBase

            var c = builder.Build();

            var matching = c.Resolve<IEnumerable<IBase>>();

            Console.WriteLine(matching.Count());
        }

    }
}

上面将2写入控制台，因为它找到了两个匹配项。