打印此数组的最简单方法

Question

这段代码所做的只是将一个句子分解为单个单词，例如：您输入My name is John ，它返回：

1. 我的
2. 姓名
3. 是
4. 约翰

我想知道是否有更好的方法来重写这个？

int main() {
    int w_size = 0;
    bool check_bool = false;
    char l_str[81];
    char *ptr_to_word[81];

    for (char *res_p = &(l_str[0]); *res_p != '\0'; res_p++) {
        if ((*res_p != '.') && (*res_p != ',') && (*res_p != ' ') && (check_bool == false)) {
            ptr_to_word[w_size] = res_p;
            w_size++;
            check_bool = true;
        }
        if (((*res_p == '.') || (*res_p == ',') || (*res_p == ' ')) && (check_bool == true)) {
            check_bool = false;
        }
    }

    if (w_size == 0) {
        printf("no solution");
    } else {
        for (int i = 0; i < w_size; i++) {
            char *a = ptr_to_word[i];
            while ((*a != ',') && (*a != '.') && (*a != '\0') && (*a != ' ')) {
                printf("%c", *a);
                a++;
            }
            printf("\n");
        }
    }
    return 0;
}

Answer 1

以下建议的代码：

1. 提示用户将句子分成单词
2. 干净地编译
3. 执行所需的功能

现在，建议的代码：（按 chqrlie 编辑）

#include <stdio.h>
#include <string.h>

#define MAX_BUF_LEN 1024
#define MAX_WORDS 100


int main( void )
{
    char buffer[ MAX_BUF_LEN ] = {0};
    char *words[ MAX_WORDS ] = {NULL};

    printf( "%s\n", "Please enter a sentence to be divided into words" );

    if( fgets( buffer, sizeof( buffer ), stdin ) )
    {
        size_t wordCount = 0;
        char *token;

        token = strtok( buffer, ",. " );
        while( wordCount < MAX_WORDS && token )
        {
            words[ wordCount ] = token;
            wordCount++;
            token = strtok( NULL, ",. " );
        }

        for( size_t i = 0; i < wordCount; i++ )
        {
            printf( "%zu: %s\n\n", i+1, words[i] );
        }
    }
}

以下是建议代码的典型运行结果：

Please enter a sentence to be divided into words
This is a sentence to be divided into words
1: This

2: is

3: a

4: sentence

5: to

6: be

7: divided

8: into

9: words

Answer 2

如果不需要将单词存储到数组中，可以直接 output ：

#include <stdio.h>
#include <string.h>

int main() {
    char str[81];

    printf("Enter string: ");
    if (fgets(str, sizeof str, stdin)) {
        int pos = 0, len, index = 1;
        for (;;) {
            /* skip initial separators */
            pos += strspn(str + pos, ",.\n ");
            if (str[pos] == '\0')
                break;
            /* compute the length of the word */
            len = strcspn(str + pos, ",.\n ");
            printf("%d: %.*s\n", index++, len, str + pos);
            pos += len;
        }
    }
    return 0;
}