[英]How to create java json dto for array or lists (non item name)?
我尝试从 controller 输入 json 读取
当我在节点中使用名称时,一切正常
有json
{
"itemList": [
{
"name": "Alex",
"surname": "Ivanov",
"age": "25"
},
{
"name": "Daria",
"surname": "Ivanova",
"age": "23"
}
]
}
json的根目录中有 itemList
我可以通过这些课程来抓住它
controller
@RequestMapping(value = "/users",
consumes = MediaType.APPLICATION_JSON_UTF8_VALUE,
produces = MediaType.APPLICATION_JSON_UTF8_VALUE)
public class UserController {
@Post
public ResponseEntity add(@RequestBody UserDto user) {
//todo check breack point hear
return new ResponseEntity<UserDto>(user, null, HttpStatus.OK);
}
}
和 model
@RequiredArgsConstructor
@Getter
@Setter
@ToString
@EqualsAndHashCode
public class UserDto implements Serializable {
public List<UserItem> itemList;
}
@RequiredArgsConstructor
@Getter
@Setter
@ToString
@EqualsAndHashCode
public class UserItem implements Serializable {
private String name;
private String surname;
private String age;
}
但是,我真的需要,我需要像这样解析 json :
只是没有名称的对象中的项目
{
[
{
"name": "Alex",
"surname": "Ivanov",
"age": "25"
},
{
"name": "Daria",
"surname": "Ivanova",
"age": "23"
}
]
}
怎么做?
这是一个畸形的 JSON object。 里面的数组没有任何键。
{
[
{
"name": "Alex",
"surname": "Ivanov",
"age": "25"
},
{
"name": "Daria",
"surname": "Ivanova",
"age": "23"
}
]
}
我认为您正在寻找的是 JSON 阵列:
[
{
"name": "Alex",
"surname": "Ivanov",
"age": "25"
},
{
"name": "Daria",
"surname": "Ivanova",
"age": "23"
}
]
要解析此 JSON 数组,只需修改您的 Controller 以接受UserItem
列表:
@RequestBody List<UserItem> users
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