使用 Sequelize 的 INSERT 和 UPDATE 查询中的意外顺序

Question

首先，我将简要解释我正在尝试做什么以及相关的模型。

拥有一个 trackingIds 数组（10 个元素），使用这个 trackingId 和一个“免费”调色板创建一个染色体

考虑：

Project.hasMany(models.Palette);
Project.hasMany(models.Chromosome);
Chromosome.hasOne(models.Palette);
Palette.belongsTo(models.Project, {foreignKey: 'projectId', as: 'project'});
Palette.belongsTo(models.Chromosome, {foreignKey: 'chromosomeId', as: 'chromosome'});

现在，我的代码看起来像这样：

freeTrackingIds.forEach(async (trackingId) => {
    // Since the project has many palettes, I want to assign to the chromosome one palette that is free (this means, that has not been assigned to any chromosome yet).
    // I tried to reload() the project to fetch the changes in its palettes in previous iterations
    const availablePalettes = (await project.reload()).palettes.filter((palette) => !palette.chromosomeId);

    // Choosing a random palette from my available palettes. Yes, there might be better ways to achieve this. 
    const randomPalette = availablePalettes[Math.floor(Math.random() * availablePalettes.length)];

    // Creating the new chromosome for the project with the trackingId 
    const chromosome = await Chromosome.create({ projectId: project.id, trackingId: trackingId });

    // Linking the Palette to the chromosome
    randomPalette.chromosomeId = chromosome.id;
    await randomPalette.save();
  });

我注意到， availablePalettes语句会检索我在此 forEach 的先前迭代中分配的调色板（这就是我决定每次都重新加载项目实体的原因）。

即使重新加载项目（返回其免费可用的调色板）我也经历过这一点。 检查我的日志我注意到：

Executing (default): INSERT INTO "Chromosomes" ("id","trackingId","elements","timesRequested","generation","createdAt","updatedAt","projectId") VALUES (DEFAULT,$1,$2,$3,$4,$5,$6,$7) RETURNING *;
Executing (default): INSERT INTO "Chromosomes" ("id","trackingId","elements","timesRequested","generation","createdAt","updatedAt","projectId") VALUES (DEFAULT,$1,$2,$3,$4,$5,$6,$7) RETURNING *;
Executing (default): INSERT INTO "Chromosomes" ("id","trackingId","elements","timesRequested","generation","createdAt","updatedAt","projectId") VALUES (DEFAULT,$1,$2,$3,$4,$5,$6,$7) RETURNING *;
Executing (default): INSERT INTO "Chromosomes" ("id","trackingId","elements","timesRequested","generation","createdAt","updatedAt","projectId") VALUES (DEFAULT,$1,$2,$3,$4,$5,$6,$7) RETURNING *;
Executing (default): INSERT INTO "Chromosomes" ("id","trackingId","elements","timesRequested","generation","createdAt","updatedAt","projectId") VALUES (DEFAULT,$1,$2,$3,$4,$5,$6,$7) RETURNING *;
Executing (default): INSERT INTO "Chromosomes" ("id","trackingId","elements","timesRequested","generation","createdAt","updatedAt","projectId") VALUES (DEFAULT,$1,$2,$3,$4,$5,$6,$7) RETURNING *;
Executing (default): INSERT INTO "Chromosomes" ("id","trackingId","elements","timesRequested","generation","createdAt","updatedAt","projectId") VALUES (DEFAULT,$1,$2,$3,$4,$5,$6,$7) RETURNING *;
Executing (default): INSERT INTO "Chromosomes" ("id","trackingId","elements","timesRequested","generation","createdAt","updatedAt","projectId") VALUES (DEFAULT,$1,$2,$3,$4,$5,$6,$7) RETURNING *;
Executing (default): INSERT INTO "Chromosomes" ("id","trackingId","elements","timesRequested","generation","createdAt","updatedAt","projectId") VALUES (DEFAULT,$1,$2,$3,$4,$5,$6,$7) RETURNING *;
Executing (default): UPDATE "Palettes" SET "chromosomeId"=$1,"updatedAt"=$2 WHERE "id" = $3
Executing (default): UPDATE "Palettes" SET "chromosomeId"=$1,"updatedAt"=$2 WHERE "id" = $3
Executing (default): UPDATE "Palettes" SET "chromosomeId"=$1,"updatedAt"=$2 WHERE "id" = $3
Executing (default): UPDATE "Palettes" SET "chromosomeId"=$1,"updatedAt"=$2 WHERE "id" = $3
Executing (default): UPDATE "Palettes" SET "chromosomeId"=$1,"updatedAt"=$2 WHERE "id" = $3
Executing (default): UPDATE "Palettes" SET "chromosomeId"=$1,"updatedAt"=$2 WHERE "id" = $3
Executing (default): UPDATE "Palettes" SET "chromosomeId"=$1,"updatedAt"=$2 WHERE "id" = $3
Executing (default): UPDATE "Palettes" SET "chromosomeId"=$1,"updatedAt"=$2 WHERE "id" = $3
Executing (default): UPDATE "Palettes" SET "chromosomeId"=$1,"updatedAt"=$2 WHERE "id" = $3

我不确定这是否完全基于时间，但看起来 sequelize（当然是由于性能原因）在分配托盘之前完成了我所有的染色体创建。 这可能是为什么 availablePalettes 返回在此 forEach() 的先前迭代中分配给 Chromosomes 的调色板的原因吗？

暂时就这些了，先谢谢了！

Answer 1

数组 object 的 forEach 函数不支持异步语法。 使用“为”：

forof (const trackingId of freeTrackingIds) {
// Since the project has many palettes, I want to assign to the chromosome one palette that is free (this means, that has not been assigned to any chromosome yet).
    // I tried to reload() the project to fetch the changes in its palettes in previous iterations
    const availablePalettes = (await project.reload()).palettes.filter((palette) => !palette.chromosomeId);

    // Choosing a random palette from my available palettes. Yes, there might be better ways to achieve this. 
    const randomPalette = availablePalettes[Math.floor(Math.random() * availablePalettes.length)];

    // Creating the new chromosome for the project with the trackingId 
    const chromosome = await Chromosome.create({ projectId: project.id, trackingId: trackingId });

    // Linking the Palette to the chromosome
    randomPalette.chromosomeId = chromosome.id;
    await randomPalette.save();  
}

我还建议您将事务用于此类批处理操作。