SQL 声明列中的 SUM 值到总计和按 id 分组

Question

你好互联网的人们。

我再次征求你的意见。

我有多个抄表器每 5 分钟收集一次功耗并存储到 MS SQL 数据库中。 我执行 SQL 查询以从所有抄表员那里获取一整天的数据，并检查它每五分钟使用了多少电量并返回为'

已消费

' 结果。 这是我用来获取数据的 SQL 语法：

SELECT Dep_Name, DoD, 
Convert(FLOAT,T_Energy_A) - lag(T_Energy_A) 
OVER(PARTITION BY Meter_ID ORDER BY DoD) AS Consumed
FROM Meter_Data
WHERE DoD>= DATEADD(HOUR,-1, GETDATE()) 
ORDER BY dateOfData DESC

我得到的结果是这样的：

Dep_Name           DoD               Consumed
Bath 6  2020-04-23 17:50:05.253 181
RPi Bath 5  2020-04-23 17:50:04.863 89
RPi Bath 4  2020-04-23 17:50:04.497 136
RPi Bath 3  2020-04-23 17:50:04.113 14
Solder Bath 6   2020-04-23 17:50:03.727 220
Solder Bath 5   2020-04-23 17:50:03.367 1261
Solder Bath 4   2020-04-23 17:50:02.997 409
Solder Bath 3   2020-04-23 17:50:02.590 0
Reflow 10   2020-04-23 17:50:02.287 440
Reflow 9    2020-04-23 17:50:02.197 244
Reflow 8    2020-04-23 17:50:02.020 361
Cam2    2020-04-23 17:50:01.787 180
Reflow 7    2020-04-23 17:50:01.457 366
Reflow 6    2020-04-23 17:50:01.030 506
Reflow 5    2020-04-23 17:50:00.837 453
Reflow 4    2020-04-23 17:50:00.770 280
Reflow 3    2020-04-23 17:50:00.697 243
Reflow 2    2020-04-23 17:50:00.630 389
Bath 6  2020-04-23 17:45:05.907 180
RPi Bath 5  2020-04-23 17:45:05.627 89
RPi Bath 4  2020-04-23 17:45:05.213 137
RPi Bath 3  2020-04-23 17:45:04.967 13
Solder Bath 6   2020-04-23 17:45:04.580 240
Solder Bath 5   2020-04-23 17:45:04.203 1254
Solder Bath 4   2020-04-23 17:45:03.967 413
Solder Bath 3   2020-04-23 17:45:03.807 0
Reflow 10   2020-04-23 17:45:03.560 493
Reflow 9    2020-04-23 17:45:03.163 245
Reflow 8    2020-04-23 17:45:02.807 360
Cam2    2020-04-23 17:45:02.433 179
Reflow 7    2020-04-23 17:45:02.063 379
Reflow 6    2020-04-23 17:45:01.473 505
Reflow 5    2020-04-23 17:45:01.383 450
Reflow 4    2020-04-23 17:45:01.157 279
Reflow 3    2020-04-23 17:45:00.780 242
Reflow 2    2020-04-23 17:45:00.657 387
Bath 6  2020-04-23 17:40:06.247 181
RPi Bath 5  2020-04-23 17:40:05.853 89
RPi Bath 4  2020-04-23 17:40:05.477 137
RPi Bath 3  2020-04-23 17:40:05.060 14
Solder Bath 6   2020-04-23 17:40:04.667 197
Solder Bath 5   2020-04-23 17:40:04.283 1212
Solder Bath 4   2020-04-23 17:40:03.887 385
Solder Bath 3   2020-04-23 17:40:03.547 0
Reflow 10   2020-04-23 17:40:03.280 495
Reflow 9    2020-04-23 17:40:03.063 244
Reflow 8    2020-04-23 17:40:02.600 361
Cam2    2020-04-23 17:40:02.303 178
Reflow 7    2020-04-23 17:40:01.943 353
Reflow 6    2020-04-23 17:40:01.500 508
Reflow 5    2020-04-23 17:40:01.280 449
Reflow 4    2020-04-23 17:40:01.040 280
Reflow 3    2020-04-23 17:40:00.687 241
Reflow 2    2020-04-23 17:40:00.620 387
Bath 6  2020-04-23 17:35:06.150 181
RPi Bath 5  2020-04-23 17:35:05.760 89
RPi Bath 4  2020-04-23 17:35:05.303 137
RPi Bath 3  2020-04-23 17:35:04.960 14
Solder Bath 6   2020-04-23 17:35:04.597 213
Solder Bath 5   2020-04-23 17:35:04.360 1178

现在我想将所有“已使用”列数据汇总为每个部门的 totalPower，并在 1 天间隔内按 Dep_Name 分组？ 像这样的东西：

Dep_Name      totalPower
Bath 6          123
RPi Bath 5      321
RPi Bath 4      1566
RPi Bath 3      1134
Solder Bath 6   ...
Solder Bath 5   ...
Solder Bath 4   ...
...             ...

有可能这样做吗？ 如果是，我该怎么做？

我对这一切都很陌生，所以我不知道。

Answer 1

如果T_Energy_A一直在增加，你可以这样做：

select dep_name, max(t_energy_a) - min(t_energy_a) totalpower
from meter_data
where dod >= dateadd(hour,-1, getdate()) 
group by dep_name

如果你每天都想要这个：

select cast(dod as date) dod_day, dep_name, max(t_energy_a) - min(t_energy_a) totalpower
from meter_data
group by cast(dod as date), dep_name
order by dod_day, dep_name

否则，您只需向现有查询添加一级聚合：

select dep_name, cast(dod as date) dod_day, sum(consumed) totalpower
from (
    select 
        dep_name, 
        dod, 
        t_energy_a - lag(t_energy_a) over(partition by meter_id order by dod) as consumed
    from meter_data
) t
group by cast(dod as date), dep_name
order by dod_day, dep_name