PHP 在多维数组中推送简单数组值不起作用

Question

编辑：更新的代码。 请查看注释行：

这是我的问题：

我有 2 个 arrays：

$numbers = array(0,3,8);

$data = array('January' => array('BATH' => array('ID', 'user', 'type'), 'KITCHEN' => array('ID', 'user', 'type')), 'february' => array('BATH' => array('ID', 'user', 'type'), 'KITCHEN' => array('ID', 'user', 'type')), 'march' => array('BATH' => array('ID', 'user', 'type'), 'KITCHEN' => array('ID', 'user', 'type')));

预期的 output 必须是：

array (size=6)
  'January' => 
    array (size=2)
      'BATH' => 
        array (size=3)
          0 => string 'ID' (length=2)
          1 => string 'user' (length=4)
          2 => string 'type' (length=4)
      'KITCHEN' => 
        array (size=3)
          0 => string 'ID' (length=2)
          1 => string 'user' (length=4)
          2 => string 'type' (length=4)
      'total_lunar' => int '0' // // This is the first value from first array
  'february' => 
    array (size=2)
      'BATH' => 
        array (size=3)
          0 => string 'ID' (length=2)
          1 => string 'user' (length=4)
          2 => string 'type' (length=4)
      'KITCHEN' => 
        array (size=3)
          0 => string 'ID' (length=2)
          1 => string 'user' (length=4)
          2 => string 'type' (length=4)
       'total_lunar' => int '3' // This is the second value from first array
  'march' => 
    array (size=2)
      'BATH' => 
        array (size=3)
          0 => string 'ID' (length=2)
          1 => string 'user' (length=4)
          2 => string 'type' (length=4)
      'KITCHEN' => 
        array (size=3)
          0 => string 'ID' (length=2)
          1 => string 'user' (length=4)
          2 => string 'type' (length=4)
       'total_lunar' => int '8' // This is the last value from first array

我的 PHP 代码是：

for ($i = 0; $i < count($numbers); $i++) 
{
    foreach ($data as $key => $value) 
    {
        $data[$key]['total_lunar'][$i] =  $numbers[$i];
    }
}

我不知道为什么，结果设置了每个数组，但不是第一个数组的每个值：

array (size=6)
  'January' => 
    array (size=2)
      'BATH' => 
        array (size=3)
          0 => string 'ID' (length=2)
          1 => string 'user' (length=4)
          2 => string 'type' (length=4)
      'KITCHEN' => 
        array (size=3)
          0 => string 'ID' (length=2)
          1 => string 'user' (length=4)
          2 => string 'type' (length=4)
      'total_lunar' => 
          array (size=3)
             0 => int 0
             1 => int 3
             2 => int 8
  'february' => 
    array (size=2)
      'BATH' => 
        array (size=3)
          0 => string 'ID' (length=2)
          1 => string 'user' (length=4)
          2 => string 'type' (length=4)
      'KITCHEN' => 
        array (size=3)
          0 => string 'ID' (length=2)
          1 => string 'user' (length=4)
          2 => string 'type' (length=4)
       'total_lunar' => 
          array (size=3)
             0 => int 0
             1 => int 3
             2 => int 8
  'march' => 
    array (size=2)
      'BATH' => 
        array (size=3)
          0 => string 'ID' (length=2)
          1 => string 'user' (length=4)
          2 => string 'type' (length=4)
      'KITCHEN' => 
        array (size=3)
          0 => string 'ID' (length=2)
          1 => string 'user' (length=4)
          2 => string 'type' (length=4)
       'total_lunar' => 
          array (size=3)
             0 => int 0
             1 => int 3
             2 => int 8

['total_lunar']键应该返回一个值作为上面预期的 output，而不是所有数组值。 到处寻找解决方案，但无法解决这个问题。

Answer 1

把事情简单化。 我想这就是你要找的吗？

$n=0;
foreach($data as &$d) {
    $d['total_lunar'] = $numbers[$n++];
}

预期的 output 你会使用这个：

echo '<pre>';
print_r($data);
echo '</pre>';