Minecraft Player On World 加入活动

Question

我是 Java 的新手，我该如何处理当前玩家加入世界？

package page.a0x77.kubecraft;

import net.minecraft.block.Block;
import net.minecraft.client.Minecraft;
import net.minecraft.entity.player.EntityPlayer;
import net.minecraft.item.Item;
import net.minecraftforge.client.ClientCommandHandler;
import net.minecraftforge.event.RegistryEvent;
import net.minecraftforge.event.entity.EntityJoinWorldEvent;
import net.minecraftforge.event.entity.player.*;
import net.minecraftforge.fml.common.event.FMLInitializationEvent;
import net.minecraftforge.fml.common.event.FMLPostInitializationEvent;
import net.minecraftforge.fml.common.event.FMLPreInitializationEvent;
import net.minecraftforge.fml.common.eventhandler.SubscribeEvent;
import net.minecraftforge.fml.common.Mod;
import net.minecraftforge.fml.common.gameevent.PlayerEvent;
import net.minecraftforge.fml.common.registry.GameRegistry;

@Mod(
        modid = Kubecraft.MOD_ID,
        name = Kubecraft.MOD_NAME,
        version = Kubecraft.VERSION
)
public class Kubecraft {

    @SubscribeEvent
    public void playerLoggedInEvent(EntityJoinWorldEvent event) {
//        ClientCommandHandler.instance.executeCommand(Minecraft.getMinecraft().player, "your command");
            System.out.println("TEST");
    }

}

我想在玩家加入时进行自动身份验证，在加入时发送消息聊天。

Answer 1

你应该使用：

@EventBusSubscriber
public static class Class {
  @SubscribeEvent
  public static void onEvent(EntityJoinWorldEvent event) {
      if ((event.getEntity() instanceof PlayerEntity)) {
        LogManager.getLogger().info("Joined!");
      }
  }
}

我想也许你需要播放器的实例才能让它工作。

Answer 2

... @Mod( modid = Kubecraft.MOD_ID, name = Kubecraft.MOD_NAME, version = Kubecraft.VERSION ) public class Kubecraft { ... @SubscribeEvent public static void onEvent(EntityJoinWorldEvent event) { Timer timer = new Timer(3000, new ActionListener() { @Override public void actionPerformed(java.awt.event.ActionEvent e) { if(!sent) Minecraft.getMinecraft().player.sendChatMessage("/setblock ~ ~ ~ grass"); sent = true; } }); timer.setRepeats(false); // Only execute once if(!sent) { timer.start(); } } } ...