按数字和字母对 javascript 数组进行排序

Question

我想对这个 javascript 数组进行排序：

 [103,3,4,6,8,"8L",67,1,11,19,68,86,107,"9L"];

按数字和字母排序，结果将如下所示：

 [1,3,4,6,8,"8L","9L",11,19,67,68,86,103,107];

当我尝试使用sort()时，它不起作用：

 [1,3,4,6,8,68,103,"8L",11,19,67,86,107,"9L"]; // 8L and 9L are in the wrong place

 // correct wanted order var correct = [1,3,4,6,8,"8L","9L",11,19,67,68,86,103,107]; document.body.innerHTML += '<b>correct wanted order:</b> <pre>' + JSON.stringify(correct) + '</pre>'; // array to order var unordered = [103,3,4,6,8,"8L",67,1,11,19,68,86,107,"9L"]; document.body.innerHTML += '<b>array to order:</b> <pre>' + JSON.stringify(unordered) + '</pre>'; unordered = unordered.map(item => { return item; }); var ordered = unordered.sort(function(a, b) { return a - b; }); document.body.innerHTML += '<b>order attempt:</b> <pre>' + JSON.stringify(ordered) + '</pre>';

Answer 1

您可以使用数组.sort()和localeCompare()方法通过传递{numeric: true}选项轻松地做到这一点，例如：

 var unordered = [103,3,4,6,8,"8L",67,1,11,19,68,86,107,"9L"]; var correct = unordered.sort((a,b) => a.toString().localeCompare(b.toString(), undefined, {numeric: true})) console.log( correct )

 .as-console-wrapper { max-height: 100%;important: top; 0; }

Answer 2

看起来您希望首先将排序 function 中的所有内容都视为字符串。 然后从字符串的rest中拆分出数字，分别测试。 像这样的东西：

const ordered = unordered.sort(function(a, b) {
  // Break apart the assumed strings (Numbers then everything else)
  const [, aNumber, aString] = `${a}`.match(/(\d*)(.*)/);
  const [, bNumber, bString] = `${b}`.match(/(\d*)(.*)/);

  // Test numbers
  if(Number(aNumber) < Number(bNumber)) return -1;
  if(Number(aNumber) > Number(bNumber)) return 1;

  // Test letters if there is a tie
  return aString < bString ? -1 : 1;
});