[英]How to deserialize this xml to objects?
我正在获取以下格式的数据:
<ReplyUserAccount xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" requestid="" version="1.0" xmlns="url">
<Sender partnerid="xx">xx</Sender>
<Users>
<User method="GET" ResultCode="OK" Description="">
<Guid>xx</Guid>
<FirstName>xx</FirstName>
<LastName>xx</LastName>
<Phone>xx</Phone>
<Mobile>xx</Mobile>
<Email>xx</Email>
<EmplNo>xx</EmplNo>
<TacPermission />
<InvPermission>xx</InvPermission>
<CustomerId>xx</CustomerId>
</User>
</Users>
</ReplyUserAccount>
使用以下 C# 对象:
[XmlRoot("ReplyUserAccount")]
public class ReplyUserAccount
{
[XmlElement("Users")]
public Users Users{ get; set; }
}
[XmlType("Users")]
public class Users
{
[XmlElement("User")]
public List<User> UserList{ get; set; }
}
[XmlType("User")]
public class User
{
[XmlElement("EmplNo")]
public string Id{ get; set; }
[XmlElement("Guid")]
public string Guid { get; set; } = null;
[XmlElement("Email")]
public string Email { get; set; }
[XmlElement("FirstName")]
public string FirstName { get; set; }
[XmlElement("LastName")]
public string LastName { get; set; }
public bool Active { get; set; } = true;
public string PhoneNumber { get; set; } = null;
}
以及以下反序列化:
var result = await httpClient.GetAsync(url);
var xdoc = XDocument.Parse(await result.Content.ReadAsStringAsync());
XmlSerializer serializer = new XmlSerializer(typeof(ReplyUserAccount));
var content = xdoc.ToString();
TextReader reader = new StringReader(content);
var res = (ReplyUserAccount)serializer.Deserialize(reader);
但我收到以下错误: InvalidOperationException: <ReplyUserAccount xmlns='xxx'> was not expected
。
对于如何正确反序列化这个特定的 xml 数据,我有点迷茫。 非常感谢您对此提供的任何和所有帮助。
要修复错误,您必须在反序列化之前删除 xml 文本中的xmlns和xsi 。 您可以像这样删除xmlns和xsi :
var content = xdoc.ToString();
string strXMLPattern = @"xmlns(:\w+)?=""([^""]+)""|xsi(:\w+)?=""([^""]+)""";
content = Regex.Replace(content, strXMLPattern, "");
因此方法应该如下
var result = await httpClient.GetAsync(url);
var xdoc = XDocument.Parse(await result.Content.ReadAsStringAsync());
XmlSerializer serializer = new XmlSerializer(typeof(ReplyUserAccount));
var content = xdoc.ToString();
string strXMLPattern = @"xmlns(:\w+)?=""([^""]+)""|xsi(:\w+)?=""([^""]+)""";
content = Regex.Replace(content, strXMLPattern, "");
TextReader reader = new StringReader(content);
var res = (ReplyUserAccount)serializer.Deserialize(reader);
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