计算 2 个子查询，然后按日期分组 - mysql

Question

我有这张桌子

我想先做子查询，然后将它们按日期分组

预期结果应该是这样的：

正在运行此查询

(
SELECT DATE_FORMAT(dd1.modified_datetime,'%Y-%m-%d') as date, (v1+v2) as value FROM
    (SELECT modified_datetime, Sum(data->"$.amount") as v1
        FROM transactions
        GROUP BY modified_datetime) as dd1 ,            
    (SELECT modified_datetime, MAX(data->"$.amount") as v2
        FROM transactions
        GROUP BY modified_datetime) as dd2

    GROUP BY dd1.modified_datetime, value
)

并得到这个结果

感谢您的帮助

Answer 1

在子查询和每个下一个查询之间使用JOIN ：

(SELECT modified_datetime, Sum(data->"$.amount") as v1
    FROM transactions
    GROUP BY modified_datetime) as dd1 JOIN
(SELECT modified_datetime, MAX(data->"$.amount") as v2
    FROM transactions
    GROUP BY modified_datetime) as dd2 ON dd1.modified_datetime=dd2.modified_datetime

Answer 2

如果我正确地跟随你，你可以使用union all和聚合：

select date_format(dt, '%Y-%m-%d') dt_day, sum(amount) value
from (
    select modified_datetime dt, data ->> '$.amount' amount from transactions
    union all 
    select created_datetime, data ->> '$.amount' from transactions
) t
group by dt_day
order by dt_day