如何只加入laravel表的最后一条记录？

Question

我有两个表beneficiaries和accommodation_histories历史，我只想将accommodation_histories历史的最后记录加入beneficiaries 。

到目前为止，这是我的方法：

public function getQuery(): Builder
{
    return DB::table('beneficiaries')
        ->select([
            'beneficiaries.id',
            'media.id as media',
            'beneficiaries.name as beneficiary_name',
            'beneficiaries.surname',
            'beneficiaries.gender',
            'beneficiaries.date_of_birth',
            'countries.name as country_of_birth',
            'accommodation_histories.center as center',
            'accommodation_histories.date_of_receipt as date_of_receipt',
            'accommodation_histories.release_date as release_date',
        ])
        ->leftJoin('media', 'media.model_id', '=', 'beneficiaries.id')
        ->join('countries', 'countries.id', '=', 'beneficiaries.country_of_birth')
        ->join('accommodation_histories', 'accommodation_histories.beneficiary', '=', 'beneficiaries.id');
}

Answer 1

您可以在家长 model（受益人）处执行如下操作：

public function accommodation_histories()
{
    return $this->hasOne('App\Accommodation_histories')->orderBy('id', 'desc');
}