如何防止 javascript object 被转换为长度为 1 的对象数组？

Question

我正在处理我的第一个单独的 ReactJS/Redux 项目，事情进展顺利，直到我在 Redux 商店中使用 object 时，它总是应该是一个单一的 ZA8CFDE6331BD4B66AC96F8911C。 当我将 object 从存储的一部分（源键的一个元素）复制到另一部分（selectedItems 键）时，object 被存储为长度为 1 的数组，这不是我传入的数据（它只是一个对象）。 我可以忍受这一点，只需将该存储变量作为数组读出，然后只使用元素 0，除非当我在 reducer 中调用另一个方法来替换存储中的该变量时，该方法将新数据存储为单个 object。 我的偏好是让所有东西都存储一个 object 但我不知道该怎么做，无论如何：这是一些减速器代码：

const initialState = {
    sources: [
        {
            id: 1,
            mfg: 'GE',
            system: 'Smart bed',
            model: '01',
            name: 'GE smart bed'
        },
        {
            id: 2,
            mfg: 'IBM',
            system: 'Patient monitor',
            model: '03',
            name: 'IBM patient monitor'
        }
    ],
    error: null,
    loading: false,
    purchased: false,
    selectedItem: {}
};

// This is called when a user selects one of sources in the UI
// the Id of the selected sources object is passed in as action.id
// This method creates an array in state.selectedItem 
const alertSourceSelect = ( state, action ) => {
    let selectedItem = state.sources.filter(function (item) {
        return item.id === action.id;
    });

    if (!selectedItem) selectedItem = {};
    return {...state, selectedItem: selectedItem};
};

// When someone edits the selected source, this takes the field name and new value to 
// replace in the selected source object and does so. Those values are stored in 
// action.field and action.value . However, when the selected source object is updated
// it is updated as a single object and not as an array.
const selectedSourceEdit = ( state, action ) => {
    return {
        ...state,
        selectedItem: updateObject(state.selectedItem[0], { [action.field] : action.value })
    };
};

const reducer = (state = initialState, action) =>  {
        switch (action.type) {
        case actionTypes.ALERT_SOURCE_SELECT: return alertSourceSelect( state, action );
        case actionTypes.ALERT_SELECTED_SOURCE_EDIT: return selectedSourceEdit( state, action );
        default: return state;
    }

这是 updateObject 方法（对不起，我遗漏了它）：

export const updateObject = (oldObject, updatedProperties) => {
    return {
        ...oldObject,
        ...updatedProperties
    }
};

Answer 1

问题： updateObject返回 object 而不是数组，并且您将selectedItem维护为数组而不是 object

export const updateObject = (oldObject, updatedProperties) => {
    return {
        ...oldObject,
        ...updatedProperties
    }
};

---

解决方案：

从updateObject返回数组：

export const updateObject = (oldObject, updatedProperties) => {
    return [{
        ...oldObject,
        ...updatedProperties
    }]
};

或制作返回的 object 数组

const selectedSourceEdit = ( state, action ) => {
    return {
        ...state,
        selectedItem: [updateObject(state.selectedItem[0], { [action.field] : action.value })]
    };
};