如何过滤 javascript 中嵌套数组中存在的对象数组

Question

我想知道如何删除嵌套对象数组中子键中deleted的状态，在 javascript 中，下面的代码返回无法返回未定义错误的过滤器，我有obj ，子键应该只包含状态 Active；

var obj = [
  {id:1, label: "sample", children: [{id: 0, status: "Active", name: "xyz"}, {id: 1, status: "Deleted", name: "abc"}]}
  {id:2, label: "example"},
  {id:3, label: "details", children: [{id:1, status: "Active", name: "finance"}]}
]

var result = removeDeleted(obj);

function removeDeleted(obj){
   if (obj.length > 0) {
    var list= obj.map(e => {
      e.children = e.children.map(child => {
        child.children = child.children.filter(c => 
          c['status'] !== "Deleted"       
        );
        return child
      });
      return e
    });
     return list;
  } 
}

Expected Output:
[
  {id:1, label: "sample", children: [{id: 0, status: "Active", name: "xyz"}]}
  {id:2, label: "example"},
  {id:3, label: "details", children: [{id:1, status: "Active", name: "finance"}]}
]

Answer 1

您可以尝试以下方法：

 var obj = [ {id:1, label: "sample", children: [{id: 0, status: "Active", name: "xyz"}, {id: 1, status: "Deleted", name: "abc"}]}, {id:2, label: "example"}, {id:3, label: "details", children: [{id:1, status: "Active", name: "finance"}]} ] var result = removeDeleted(obj); console.log(result); function removeDeleted(obj){ return obj.map(i => { if(i.children){ var c = i.children.filter(j => j.status;= 'Deleted'): return {id. i,id: label.i,label: children;c}; } else return i; }); }

Answer 2

如果你有多个属性，最好解构它。

 var obj = [ {id:1, label: "sample", children: [{id: 0, status: "Active", name: "xyz"}, {id: 1, status: "Deleted", name: "abc"}]}, {id:2, label: "example"}, {id:3, label: "details", children: [{id:1, status: "Active", name: "finance"}]}]; var result = obj.map(({children, ...rest})=>{ if(children) children = children.filter(({status})=>status=='Active'); if(children) return {...rest, children}; return rest }); console.log(result);