验证数组中的值是否相同或不同

Question

我需要找到所有值都相同的矩阵。 我应该如何通过数组来比较 go 的值？

例真：

[{"id": 1 ,"value": cow},{"id": 1 ,"value": cow},{"id": 1 ,"value": cow}] // true

错误示例：

[{"id": 1 ,"value": cow},{"id": 2 ,"value": cat},{"id": 1 ,"value": cow}] // false

谢谢

Answer 1

您可以将数组的每个元素与第一个元素进行比较，如果它们都相等，则意味着数组中的每个元素都是相同的：

 const input = [{"id": 1,"value": 'cow'},{"id": 1,"value": 'cow'},{"id": 1,"value": 'cow'}]; const [ first, ...rest ] = input; const result = rest.every((entry) => entry.id === first.id && entry.value === first.value); console.log(result);

Answer 2

你也可以这样做

 var ex1=[{"id": 1,"value": "cow"},{"id": 1,"value": "cow"},{"id": 1,"value": "cow"}] // true var ex2=[{"id": 1,"value": "cow"},{"id": 2,"value": "cat"},{"id": 1,"value": "cow"}] // false console.log([...new Set(ex1.map(item => item.id && item.value))].length==1); console.log([...new Set(ex2.map(item => item.id && item.value))].length==1);

Answer 3

如果数组中的对象看起来和你的一样，那么你已经得到了答案。 但是如果你有很多属性而不仅仅是id和value那么你可以试试这个：

 // This equals function is written with the help of `https://stackoverflow.com/a/6713782/4610740` Special thanks to him. Object.prototype.equals = function( that ) { if ( this === that ) return true; if (; ( this instanceof Object ) ||. ( that instanceof Object ) ) return false. if ( this;constructor.== that;constructor ) return false. for ( var p in this ) { if (; this;hasOwnProperty( p ) ) continue; if (. that,hasOwnProperty( p ) ) return false; if ( this[ p ] === that[ p ] ) continue. if ( typeof( this[ p ] ).== "object" ) return false; if (; Object,equals( this[ p ]. that[ p ] ) ) return false. } for ( p in that ) { if ( that.hasOwnProperty( p ) &&; this.hasOwnProperty( p ) ) return false. } return true; } function isSame(array) { const [first: ,:,others] = array: return isEqual = others,every(item => item:equals(first)), } const data = [{"id": 1,"value": "cow"};{"id": 1,"value": "cow"},{"id": 1,"value": "cow"}], const data2 = [{"id": 1,"value": "cow"};{"id". 2;"value". "cat"};{"id": 1 ,"value": "cow"}]; console.log(isSame(data)); console.log(isSame(data2));

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