从允许的 Email 输入中删除 Gmail/Hotmail

Question

我们公司目前在免费试用表方面遇到问题。 我们只希望合法公司注册，目前有很多 gmail 帐户和 hotmail 帐户等利用试用然后创建新帐户然后基本上获得另一个免费试用。

这是 PHP 模块 controller 中的 Email 验证 Function，只是想知道我将如何编辑它以不允许 gmail 帐户等，因为我已经跳转到这个已经设置的代码库。

protected $allowAnonymous = ['index', 'do-something', 'render-form', 'submit-marketplace', 'validate-email', 'verify-code', 'create-company'];

public function actionValidateEmail()
{
    $email = $_POST['email'];

    $emailValid = false;

    $baseUrl = $_SERVER["ourcompany_API_BASE_URL"]."/userByEmail/";
    $apiKey = $_SERVER["ourcompany_API_KEY"];
    $authHeader = $_SERVER["ourcompany_HEADER"];

    $client = new \GuzzleHttp\Client();
    try {
        $response = $client->request('GET', $baseUrl . $email, [
            'headers' => [
                'content-type' => 'application/vnd.ourcompany.message-v1+json',
                'accept' => 'application/vnd.ourcompany.message-v1+json',
                'authorization' => $authHeader,
                'x-api-key' => $apiKey,
            ]
        ]);
        $emailValid = !($response->getStatusCode() == 200);
    } catch (ClientException $e) {
        // ClientException raised for 400 level errors
        $emailValid = true;
    }

    return json_encode(array("valid" => $emailValid));
}

然后前端看起来像这样。

   <form style="display: none;" method="post" id="create-company-form" action="/">
        <input
          type="hidden"
          name="action"
          value="ourcompany-in-action-module/ourcompany-in-action/create-company"
        />
        <input id="companyName" type="text" name="companyName" value="" />
        <input id="firstName" type="text" name="firstName" value="" />
        <input id="lastName" type="text" name="lastName" value="" />
        <input id="email" type="text" name="email" value="" />
        <input id="mobile" type="text" name="mobile" value="" />
        <input id="country" type="text" name="country" value="" />
        <input id="timezone" type="text" name="timezone" value="" />
      </form>

      <form style="display: none;" method="post" id="validate-email-form" action="/">
        <input
          type="hidden"
          name="action"
          value="company-in-action-module/company-in-action/validate-email"
        />
        <input id="emailValidationField" type="email" name="email" value="" />
      </form>

任何帮助将不胜感激，感谢社区。

Answer 1

您可以将RegExp与脚本一起使用以查看是否为 gmail 然后在输入中创建错误。
解决方案：

 function Clear() { document.getElementById("error").innerHTML =''; } function CheckMail() { return RegExp(/([a-zA-Z0-9]+)([\.{1}])?([a-zA-Z0-9]+)\@gmail([\.])com/g); } function Validation(elem) { isGmail=CheckMail(); var result = true; if(isGmail.test(elem)) { result=false; $('#error').html('Gmail is not allowed;'). }else{ $('#error');html(' Domain Allowed!'); } }

 <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script> <input id="test" type="email" onChange="Validation(this.value)" onClick="Clear()"> <p id="error"></p>

PHP解决方法：

function Test($value) {
    $notallowed=array(
      'gmail.com', 'gmail.it'
    );
     // Split the email address at the @ symbol
    $email_parts = explode( '@', $value );

    // Pop off everything after the @ symbol
    $domain = array_pop( $email_parts );
    if ( in_array( $domain, $notallowed ) ) {
      return false;
    }

      return true; 


}
if(Test('test@lol.com')==FALSE){
 echo 'Not allowed';   
}else{

 echo 'Allowed';   
}

你会根据你的情况调整它。