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[英]Find the elements with different values in two different array objects in javascript
[英]Group array objects by two elements and sum values (Javascript)
我有以下情况:
我有一个由当前登录用户的所有约会组成的数组,如下所示:
this.appointments = [
{
CreatedBy: "bob",
Description: "smthng",
EndTime: "2020-06-01T17:00:00.000Z",
EndTimezone: null,
Id: 3,
IsAllDay: false,
Client: "Steven",
Location: "smthng",
RecurrenceRule: "FREQ=DAILY;INTERVAL=1;COUNT=5;",
StartTime: "2020-06-01T09:00:00.000Z",
StartTimezone: null,
Subject: "smthng",
km: 88,
week: 23,
_id: "5ecc6f4a08c79c6328974699"
},
{
CreatedBy: "bob",
Description: "smthng",
EndTime: "2020-06-08T10:30:00.000Z",
EndTimezone: null,
Id: 4,
IsAllDay: false,
Client: "Steven",
Location: "smthng",
RecurrenceRule: null,
StartTime: "2020-06-08T10:00:00.000Z",
StartTimezone: null,
Subject: "smthng" ,
km: 88,
week: 24,
_id: "5ed450d299d5303bd0338a7f"
}
]
我最终想要做的是按客户每周对数组进行分组。 因此,累积每个客户一周的所有约会时间和km
数(使用 dayjs 库)。 这是我现在拥有的.reduce
function ,它仅按客户端对数组进行分组,但还不是每周:
this.appointments.reduce(function (res, value) {
let diff = dayjs(value.EndTime).diff(dayjs(value.StartTime), "hour",true) % 60;
let count;
if(value.RecurrenceRule != null) {
count = parseInt(value.RecurrenceRule.split("COUNT=")[1]);
if(value.RecurrenceException){
if(value.RecurrenceException.match(/,/g) ) {
if(value.RecurrenceException.match(/,/g).length == 0) {
console.log(value.RecurrenceException.match(/,/g).length);
count = count -1;
}
} else if(value.RecurrenceException && value.RecurrenceException.match(/,/g).length == 1) {
console.log(value.RecurrenceException.match(/,/g).length);
count = count -2;
} else if(value.RecurrenceException && value.RecurrenceException.match(/,/g).length == 2) {
console.log(value.RecurrenceException.match(/,/g).length);
count = count -3;
} else
if(value.RecurrenceException && value.RecurrenceException.match(/,/g).length == 3) {
count = count -4;
};
}
}
else if(value.RecurrenceRule == null) {
count = 1;
}
if (!res[value.Client]) {
res[value.Client] = {
week: value.week,
km: value.km * count,
Client: value.Client,
count: count,
difference: diff * count
};
result.push(res[value.Client]);
} else {
res[value.Client].km += value.km * count;
res[value.Client].difference += diff * count;
}
return res;
}, {});
我该如何 go 这种情况现在的 output 不是创建两行(第 23 周和第 24 周),而是将第 23 周 Steven 的所有约会相加,这是不正确的,因为另一周发生了 0.5 小时。
{Client: "Steven"
count: 5
difference: 40.5
km: 528
week: 23}
所以理想的 output 是:
{
Client: "Steven"
count: 5
difference: 40
km: 440
week: 23
},
{
Client: "Steven"
count: 1
difference: 0.5
km: 88
week: 24
}
只要客户不同,您就可以拥有具有相同周数的行。
我希望我说清楚了,如果您需要更多上下文,请提及
我不确定这是您的期望,我不确定如何处理差异,如果不满意,请向我解释。
var data = [ { CreatedBy: "bob", Description: "smthng", EndTime: "2020-06-01T17:00:00.000Z", EndTimezone: null, Id: 3, IsAllDay: false, Client: "Steven", Location: "smthng", RecurrenceRule: "FREQ=DAILY;INTERVAL=1;COUNT=5;", StartTime: "2020-06-01T09:00:00.000Z", StartTimezone: null, Subject: "smthng", km: 88, week: 23, _id: "5ecc6f4a08c79c6328974699" }, { CreatedBy: "bob", Description: "smthng", EndTime: "2020-06-08T10:30:00.000Z", EndTimezone: null, Id: 4, IsAllDay: false, Client: "Steven", Location: "smthng", RecurrenceRule: null, StartTime: "2020-06-08T10:00:00.000Z", StartTimezone: null, Subject: "smthng", km: 88, week: 24, _id: "5ed450d299d5303bd0338a7f" }, { CreatedBy: "bob", Description: "smthng", EndTime: "2020-06-01T17:00:00.000Z", EndTimezone: null, Id: 3, IsAllDay: false, Client: "Steven", Location: "smthng", RecurrenceRule: "FREQ=DAILY;INTERVAL=1;COUNT=5;", StartTime: "2020-06-01T09:00:00.000Z", StartTimezone: null, Subject: "smthng", km: 40, week: 23, _id: "5ecc6f4a08c79c6328974699" }, { CreatedBy: "bob", Description: "smtng", EndTime: "2020-06-01T17:00:00.000Z", EndTimezone: null, Id: 3, IsAllDay: false, Client: "ajai", Location: "smthng", RecurrenceRule: "FREQ=DAILY;INTERVAL=1;COUNT=5;", StartTime: "2020-06-01T09:00:00.000Z", StartTimezone: null, Subject: "smthng", km: 88, week: 23, _id: "5ecc6f4a08c79c6328974699" } ] let result = [] for(var i=0;i<=data.length-1;i++){ let pos = result.findIndex(el=> `${el.Client}-${el.week}`==`${data[i].Client}-${data[i].week}`) if(pos==-1){ result.push({Client: data[i]['Client'],count: 1,difference: 0,km: data[i]['km'],week: data[i]['week']}) }else{ result[pos]['count'] = result[pos]['count'] + 1; result[pos]['km'] = result[pos]['km'] + data[i]['km']; } } console.log(result)
基于@ajai 的回答(并首先使用他的输入进行比较),希望能够为您提供所需的内容(并使用reduce)。
const data = [ { CreatedBy: "bob", Description: "smthng", EndTime: "2020-06-01T17:00:00.000Z", EndTimezone: null, Id: 3, IsAllDay: false, Client: "Steven", Location: "smthng", RecurrenceRule: "FREQ=DAILY;INTERVAL=1;COUNT=5;", StartTime: "2020-06-01T09:00:00.000Z", StartTimezone: null, Subject: "smthng", km: 88, week: 23, _id: "5ecc6f4a08c79c6328974699" }, { CreatedBy: "bob", Description: "smthng", EndTime: "2020-06-08T10:30:00.000Z", EndTimezone: null, Id: 4, IsAllDay: false, Client: "Steven", Location: "smthng", RecurrenceRule: null, StartTime: "2020-06-08T10:00:00.000Z", StartTimezone: null, Subject: "smthng", km: 88, week: 24, _id: "5ed450d299d5303bd0338a7f" }, { CreatedBy: "bob", Description: "smthng", EndTime: "2020-06-01T17:00:00.000Z", EndTimezone: null, Id: 3, IsAllDay: false, Client: "Steven", Location: "smthng", RecurrenceRule: "FREQ=DAILY;INTERVAL=1;COUNT=5;", StartTime: "2020-06-01T09:00:00.000Z", StartTimezone: null, Subject: "smthng", km: 40, week: 23, _id: "5ecc6f4a08c79c6328974699" }, { CreatedBy: "bob", Description: "smtng", EndTime: "2020-06-01T17:00:00.000Z", EndTimezone: null, Id: 3, IsAllDay: false, Client: "ajai", Location: "smthng", RecurrenceRule: "FREQ=DAILY;INTERVAL=1;COUNT=5;", StartTime: "2020-06-01T09:00:00.000Z", StartTimezone: null, Subject: "smthng", km: 88, week: 23, _id: "5ecc6f4a08c79c6328974699" } ] const result = Object.values(data.reduce((aggObj, item) => { const stringID = `${item.Client}_${item.week}`; const diff = (new Date(item.EndTime) - new Date(item.StartTime))/(1000*60*60); const RecurrenceObj = item.RecurrenceRule? item.RecurrenceRule.split(";").map(a => { //console.log(a) return a.split("=") || ["_", null]; }).reduce((aggObj, [key,val]) => { aggObj[key] = val; return aggObj; }): {COUNT: 1}; if (aggObj[stringID]){ aggObj[stringID].km += (item.km * RecurrenceObj.COUNT); aggObj[stringID].count += parseInt(RecurrenceObj.COUNT); aggObj[stringID].difference += (diff * RecurrenceObj.COUNT); } else { aggObj[stringID] = { Client: item.Client, km: item.km * RecurrenceObj.COUNT, count: parseInt(RecurrenceObj.COUNT), difference: diff * RecurrenceObj.COUNT, week: item.week }; } return aggObj; }, {})); /* for(var i=0;i<=data.length-1;i++){ let pos = result.findIndex(el=> `${el.Client}-${el.week}`==`${data[i].Client}-${data[i].week}`) if(pos==-1){ result.push({Client: data[i]['Client'],count: 1,difference: 0,km: data[i]['km'],week: data[i]['week']}) }else{ result[pos]['count'] = result[pos]['count'] + 1; result[pos]['km'] = result[pos]['km'] + data[i]['km']; } } */ console.log(result)
.as-console-wrapper { max-height: 100%;important: top; 0; }
OUTPUT:
[
{
"Client": "Steven",
"km": 640,
"count": 10,
"difference": 80,
"week": 23
},
{
"Client": "Steven",
"km": 88,
"count": 1,
"difference": 0.5,
"week": 24
},
{
"Client": "ajai",
"km": 440,
"count": 5,
"difference": 40,
"week": 23
}
]
现在有了您的确切输入:
const data = [ { CreatedBy: "bob", Description: "smthng", EndTime: "2020-06-01T17:00:00.000Z", EndTimezone: null, Id: 3, IsAllDay: false, Client: "Steven", Location: "smthng", RecurrenceRule: "FREQ=DAILY;INTERVAL=1;COUNT=5;", StartTime: "2020-06-01T09:00:00.000Z", StartTimezone: null, Subject: "smthng", km: 88, week: 23, _id: "5ecc6f4a08c79c6328974699" }, { CreatedBy: "bob", Description: "smthng", EndTime: "2020-06-08T10:30:00.000Z", EndTimezone: null, Id: 4, IsAllDay: false, Client: "Steven", Location: "smthng", RecurrenceRule: null, StartTime: "2020-06-08T10:00:00.000Z", StartTimezone: null, Subject: "smthng", km: 88, week: 24, _id: "5ed450d299d5303bd0338a7f" } ] const result = Object.values(data.reduce((aggObj, item) => { const stringID = `${item.Client}_${item.week}`; const diff = (new Date(item.EndTime) - new Date(item.StartTime))/(1000*60*60); const RecurrenceObj = item.RecurrenceRule? item.RecurrenceRule.split(";").map(a => { //console.log(a) return a.split("=") || ["_", null]; }).reduce((aggObj, [key,val]) => { aggObj[key] = val; return aggObj; }): {COUNT: 1}; if (aggObj[stringID]){ aggObj[stringID].km += (item.km * RecurrenceObj.COUNT); aggObj[stringID].count += parseInt(RecurrenceObj.COUNT); aggObj[stringID].difference += (diff * RecurrenceObj.COUNT); } else { aggObj[stringID] = { Client: item.Client, km: item.km * RecurrenceObj.COUNT, count: parseInt(RecurrenceObj.COUNT), difference: diff * RecurrenceObj.COUNT, week: item.week }; } return aggObj; }, {})); /* for(var i=0;i<=data.length-1;i++){ let pos = result.findIndex(el=> `${el.Client}-${el.week}`==`${data[i].Client}-${data[i].week}`) if(pos==-1){ result.push({Client: data[i]['Client'],count: 1,difference: 0,km: data[i]['km'],week: data[i]['week']}) }else{ result[pos]['count'] = result[pos]['count'] + 1; result[pos]['km'] = result[pos]['km'] + data[i]['km']; } } */ console.log(result)
.as-console-wrapper { max-height: 100%;important: top; 0; }
OUTPUT:
[
{
"Client": "Steven",
"km": 440,
"count": 5,
"difference": 40,
"week": 23
},
{
"Client": "Steven",
"km": 88,
"count": 1,
"difference": 0.5,
"week": 24
}
]
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