[英]flutter dart JsonSerializable with inherited class
我有以下两个类,其中一个是从另一个扩展而来的,如下所示:
@JsonSerializable(nullable: true)
class Response {
final String responseCode;
final String responseMessage;
final String errorLog;
Response({this.errorLog, this.responseCode, this.responseMessage});
factory Response.fromJson(Map<String, dynamic> json) =>
_$ResponseFromJson(json);
}
..................................................... …………
@JsonSerializable(nullable: false)
class Verify extends Response {
Data data;
Verify({
this.data,
});
factory Verify.fromJson(Map<String, dynamic> json) => _$VerifyFromJson(json);
Map<String, dynamic> toJson() => _$VerifyToJson(this);
}
并且每当我尝试从验证 clasit 中读取响应class 属性时总是 null
那么请如何实现这一目标?
我已经通过将参数传递给 super 来验证 class 构造函数来解决这个问题
@JsonSerializable()
class VerifyResponse extends Response {
Data data;
VerifyResponse({
this.data,
String responseCode,
String responseMessage,
}) : super(responseCode: responseCode, responseMessage: responseMessage);
factory VerifyResponse.fromJson(Map<String, dynamic> json) =>
_$VerifyResponseFromJson(json);
Map<String, dynamic> toJson() => _$VerifyResponseToJson(this);
}
对于响应 class 它保持不变
@JsonSerializable()
class Response {
final String responseCode;
final String responseMessage;
Response({this.responseCode, this.responseMessage});
factory Response.fromJson(Map<String, dynamic> json) =>
_$ResponseFromJson(json);
}
这有点烦人,但就是这样。
您应该从响应 Class 中删除“最终”关键字
@JsonSerializable(nullable: true)
class Response {
String responseCode;
String responseMessage;
String errorLog;
Response({this.errorLog, this.responseCode, this.responseMessage});
factory Response.fromJson(Map<String, dynamic> json) =>
_$ResponseFromJson(json);
}
它通过添加super();
显式地传递给子类的构造函数。
@JsonSerializable()
class VerifyResponse extends Response {
Data data;
VerifyResponse({
this.data,
String responseCode,
String responseMessage,
//No need to list all parent class properties
}) : super();
factory VerifyResponse.fromJson(Map<String, dynamic> json) =>
_$VerifyResponseFromJson(json);
Map<String, dynamic> toJson() => _$VerifyResponseToJson(this);
}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.