[英]pine script - plot triangle if condition is true 2 times in previous 6 candles
我正在尝试 plot 一个三角形,如果在前 6 个烛台内,至少有 2 次发生移动交叉。 我有以下脚本,但我不知道如何编写 if 语句。 非常感谢您的任何建议!
//@version=4
study(title="Crossover", overlay=true,resolution="")
first = ema(close, 5)
seconds = ema(close, 13)
third = sma(close,21)
fourth = sma(close,34)
fifth = sma(close, 55)
sixth = sma(close,89)
plot(first, title="EMA 5", color=color.red, linewidth=1, transp=0)
plot(seconds, title="Ema 13", color=color.aqua, linewidth=1, transp=0)
plot(third, title="SMA 21", color=color.orange, linewidth=2, transp=0)
plot(fourth, title="SMA 34", color=color.blue, linewidth=2, transp=0)
plot(fifth, title="SMA 55", color=color.black, linewidth=2, transp=0)
plot(sixth, title="SMA 89", color=color.purple, linewidth=2, transp=0)
long1 = (first > seconds) and crossover(first,third)
long2 = (first > third) and crossover(first, seconds)
long3 = (first > fourth) and (first > seconds) and (first > third) and cross(first,fourth)
// if long1 or long2 or long3 is true 2 times in the previous 6 six candles then plot it ("long")
xxxxxx
plotshape(series=long, title="L", style=shape.triangleup, location=location.belowbar, color=color.green, text="L", size=size.small)
请参阅如何计算最后 x 条中某个条件的出现次数? 举个例子。
使用从barssince
开始的酒吧:
LENGTH = 6
count1 = barssince(long1 or long2 or long3)
count2 = count1[count1 + 1]
plotshape(count1 + count2 < LENGTH - 1, title="L", style=shape.triangleup, location=location.belowbar, color=color.green, text="L", size=size.small)
更新
实际上,我的解决方案有点过度设计,我会按照 Bjorn Mistiaen 的建议推荐sum
:
LENGTH = 6
count = sum(long1 or long2 or long3 ? 1 : 0, LENGTH)
plotshape(count >= 2, title="L", style=shape.triangleup, location=location.belowbar, color=color.green, text="L", size=size.small)
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.