[英]How to Add one row to another
我有一组数据,如图所示:
我尝试使用领先的 function 添加一月到二月,这在下图中再次显示是正确的:
而且我认为它会像 for 循环一样添加并添加到下一行,但事实并非如此。
我正在寻求有关如何像 for 循环一样一次又一次地添加数据的帮助。 我已经粘贴了我在下面使用的代码。
;WITH MonthActiveUsers AS (
SELECT MonthLogin, COUNT(MonthLogin) AS ActiveUsers
FROM #TEMPDistinctActiveUsersPerMonth DAUPM
GROUP BY MonthLogin
)
SELECT MAU.MonthLogin, (LEAD(MAU.ActiveUsers,0) OVER (ORDER BY MAU.MonthLogin ASC) + LEAD(MAU.ActiveUsers,1) OVER (ORDER BY MAU.MonthLogin ASC)) AS [Count of Active Users]
FROM
( SELECT CASE
WHEN MonthLogin = 'January'
THEN '2020-01-01'
WHEN MonthLogin = 'February'
THEN '2020-02-01'
WHEN MonthLogin = 'March'
THEN '2020-03-01'
WHEN MonthLogin = 'April'
THEN '2020-04-01'
WHEN MonthLogin = 'May'
THEN '2020-05-01'
WHEN MonthLogin = 'June'
THEN '2020-06-01'
ELSE NULL
END AS [MonthLogin]
,ActiveUsers
FROM MonthActiveUsers MAU
) MAU
期望的结果是:
January = 3313
February = 3349
March = 3398
April = 3421
May = 3437
June = 3444
我认为你想要一个 window 总和:
WITH ...
SELECT
MAU.MonthLogin,
SUM(MAU.ActiveUsers) OVER (ORDER BY MAU.MonthLogin) [Count of Active Users]
FROM ...
请注意,可以通过使用CASE
的短路形式以及混合聚合和 window 函数来稍微简化查询:
SELECT
MonthLogin,
COUNT(*) ActiveUsers,
SUM(COUNT(*)) OVER(ORDER BY MonthLogin) [Count of Active Users]
FROM (
SELECT
CASE MonthLogin
WHEN'January' THEN '2020-01-01'
WHEN'February' THEN '2020-02-01'
WHEN'March' THEN '2020-03-01'
WHEN'April' THEN '2020-04-01'
WHEN'May' THEN '2020-05-01'
WHEN'June' THEN '2020-06-01'
END AS MonthLogin
FROM #TEMPDistinctActiveUsersPerMonth
) t
GROUP BY MonthLogin
ORDER BY MonthLogin
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