Express.js：如何在 Firebase 函数中使用带有正则表达式路径模式的 app.use() 时获得“干净路径”？

Question

我的目标：当浏览器 URL 是http://localhost:5000/register时，我只想Express返回/register ，仅此而已。 但是，使用Express似乎无法轻松实现如此简单的目标。

首先，我认为在继续之前向您展示我的firebase.json是很好的：

firebase.json：

"hosting": 
    {
      "target": "store",
      "public": "store/public",
      "ignore": [
        "firebase.json",
        "**/.*",
        "**/node_modules/**"
      ],
      "rewrites": [
        {
          "source": "/app{,/**}",
          "destination": "/app/app.html"
        },
        {
          "source": "**",
          "function": "site"
        }
      ]
    }

然后在我的 Firebase 函数中， index.js ：

const functions = require('firebase-functions');
const express = require("express");
const site = express();

// Any path except /app/anything.
site.use(/^\/(?!app).*/, function (req, res, next) {
    console.log(`req.path] = ${req.path}`);
    console.log(`req.route.path] = ${req.route.path}`);
    console.log(`req.originalUrl] = ${req.originalUrl}`);
    console.log(`req.url] = ${req.url}`);
    console.log(`req.baseUrl] = ${req.baseUrl}`);
    console.log(`site.mountpath = ${site.mountpath}`);

    next();
});

site.get("/", (req, res) => {
    res.send("Homepage");
});

site.get("/register", (req, res) => {
    res.send("Registration Page");
});

exports.site = functions.https.onRequest(site);

以下是控制台结果：

i  functions: Beginning execution of "site"
>  req.path] = /
>  req.route.path] = *
>  req.originalUrl] = /firebase-project-id/us-central1/site/register
>  req.url] = /
>  req.baseUrl] = /firebase-project-id/us-central1/site/register
>  site.mountpath = /

如您所见，除了具有相似结果的如此多变体（例如/ ）之外，上述任何方法都无法帮助实现我的简单目标。 有没有其他可靠的选项可以用来获取/register而不会危险地操作/firebase-project-id/us-central1/site/register字符串？ 非常感谢！

Answer 1

参考@Doug Stevenson 在此处的帖子， req.headers['x-original-url']有效！

控制台 output：

req.headers['x-original-url'] = /register