[英]How to define member template function of variadic class template
我正在尝试使用成员模板函数实现可变参数 class 模板,其模板 arguments 独立于 class 模板参数,但我在定义成员模板时遇到了麻烦。
我将我的问题简化为尝试编译它(抱歉无法弄清楚如何进一步简化):
#include <iostream>
#include <string>
#include <typeindex>
#include <typeinfo>
#include <unordered_map>
#include <utility>
#include <vector>
template <class... Types>
class Foo {
public:
Foo();
template <class T>
T& at(const std::string& key);
template <class T>
void insert(const std::string& key, const T& value);
private:
std::tuple<std::unordered_map<std::string, Types>...> sets_;
std::unordered_map<std::type_index, size_t> type_to_pos_;
};
template<class... Types>
Foo<Types...>::Foo() {
std::vector<std::type_index> type_indices{std::type_index(typeid(Types))...};
for (size_t i = 0; i < type_indices.size(); i++) {
this->type_to_pos_.insert({type_indices[i], i});
}
}
template<class T, class... Types>
T& Foo<Types...>::at(const std::string& key) {
std::type_index type_idx{std::type_index(typeid(T))};
size_t pos;
pos = this->type_to_pos_.at(type_idx);
return std::get<pos>(this->sets_).at(key);
}
template <class T, class... Types>
void Foo<Types...>::insert(const std::string& key, const T& value) {
std::type_index type_idx{std::type_index(typeid(T))};
size_t pos;
pos = this->type_to_pos_.at(type_idx);
std::get<pos>(this->sets_).insert({key, value});
}
int main(int argc, char** argv) {
Foo<int, float, double> foo{};
foo.insert("key", 1.0f);
std::cout << foo.at<float>("key") << std::endl;
return 0;
}
尝试编译 (C++11) 时,出现以下错误:
$ make
Scanning dependencies of target test
[ 50%] Building CXX object CMakeFiles/test.dir/main.cpp.o
/Users/Jasper/cpp_projects/playground/main.cpp:33:19: error: nested name specifier 'Foo<Types...>::'
for declaration does not refer into a class, class template or class template partial
specialization
T& Foo<Types...>::at(const std::string& key) {
~~~~~~~~~~~~~~~^
/Users/Jasper/cpp_projects/playground/main.cpp:37:9: error: invalid use of 'this' outside of a
non-static member function
pos = this->type_to_pos_.at(type_idx);
^
/Users/Jasper/cpp_projects/playground/main.cpp:38:24: error: invalid use of 'this' outside of a
non-static member function
return std::get<pos>(this->sets_).at(key);
^
/Users/Jasper/cpp_projects/playground/main.cpp:38:40: error: use of undeclared identifier 'key'
return std::get<pos>(this->sets_).at(key);
^
/Users/Jasper/cpp_projects/playground/main.cpp:42:21: error: nested name specifier 'Foo<Types...>::'
for declaration does not refer into a class, class template or class template partial
specialization
void Foo<Types...>::insert(const std::string& key, const T& value) {
~~~~~~~~~~~~~~~^
/Users/Jasper/cpp_projects/playground/main.cpp:43:19: error: redefinition of 'type_idx'
std::type_index type_idx{std::type_index(typeid(T))};
^
/Users/Jasper/cpp_projects/playground/main.cpp:34:19: note: previous definition is here
std::type_index type_idx{std::type_index(typeid(T))};
^
/Users/Jasper/cpp_projects/playground/main.cpp:44:10: error: redefinition of 'pos'
size_t pos;
^
/Users/Jasper/cpp_projects/playground/main.cpp:35:10: note: previous definition is here
size_t pos;
^
/Users/Jasper/cpp_projects/playground/main.cpp:46:9: error: invalid use of 'this' outside of a
non-static member function
pos = this->type_to_pos_.at(type_idx);
^
8 errors generated.
make[2]: *** [CMakeFiles/test.dir/main.cpp.o] Error 1
make[1]: *** [CMakeFiles/test.dir/all] Error 2
make: *** [all] Error 2
我很确定它归结为第一个和第五个错误,但无法弄清楚我做错了什么。 为什么Foo<Types...>
不引用 class 模板? 我怎样才能解决这个问题?
编辑:添加了实用程序库并修复了insert
的返回值。
PS 为了简单起见,我删除了所有异常检查。
—————————- @songyuanyao 给出的答案解决了问题,但正如@songyuanyao 指出的那样,在编译时get
不知道pos
所以它不会编译。 这个解决方案有助于解决这个问题。
您应该分开两组模板参数:一组用于封闭的 class 模板,另一组用于成员 function 模板本身。 例如
template<class... Types> // for the enclosing class template
template<class T> // for the member template
T& Foo<Types...>::at(const std::string& key) {
...
}
template<class... Types> // for the enclosing class template
template<class T> // for the member template
void Foo<Types...>::insert(const std::string& key, const T& value) {
...
}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.