[英]Laravel relationship conflicts in union
我有以下 model:1-用户 model
/**
* Define user and functional area relationship
*/
public function functionalAreas()
{
return $this->belongsToMany('App\FunctionalArea', 'user_functional_areas', 'user_id', 'functional_area_id')->withPivot('id', 'is_primary')->withTimestamps();
}
和业务 model:
/**
* Define business and user functional area relationship
*/
public function functionalAreas()
{
return $this->belongsToMany('App\FunctionalArea', 'business_functional_areas', 'business_id', 'functional_area_id')->withTimestamps();
}
现在我应该将所有企业和用户显示在一个列表中,为此我从联合中使用,以下是我的查询:
public function usersAndOrganizations()
{
$users = $this->users();
$organizations = $this->organizations();
$invitees = $users->union($organizations)->paginate(10);
return response()->json($invitees);
}
private function users()
{
$users = User::byState($approved = true, 'is_approved')
->search()->select([
'id',
DB::raw("CONCAT(first_name, ' ', last_name) AS name"),
'about',
'address',
'slug',
'average_reviews',
DB::raw("'freelancer' AS type")
]);
$users = $users->with([
"functionalAreas" => function ($q) {
$q->select([
'functional_areas.id',
DB::raw("functional_areas.name_en AS name"),
]);
}
]);
return $users;
}
private function organizations()
{
$businesses = Business::where('owner_id', '!=', auth()->user()->id)->verified()
->active()->search()
->select([
'id',
'name',
'about',
'address',
'slug',
'average_reviews',
DB::raw("'business' AS type")
]);
$businesses = $businesses
->with([
"functionalAreas" => function ($q) {
$q->select([
'functional_areas.id',
DB::raw("functional_areas.name_en AS name"),
]);
}
]);
return $businesses;
}
但是上面的查询没有返回业务功能区,它的output查询是从用户关系而不是业务中使用的, with
section会生成两次如下查询:
select
`functional_areas`.`id`,
functional_areas.name_en AS name,
`user_functional_areas`.`user_id` as `pivot_user_id`,
`user_functional_areas`.`functional_area_id` as `pivot_functional_area_id`,
`user_functional_areas`.`id` as `pivot_id`,
`user_functional_areas`.`is_primary` as `pivot_is_primary`,
`user_functional_areas`.`created_at` as `pivot_created_at`,
`user_functional_areas`.`updated_at` as `pivot_updated_at`
from `functional_areas`
inner join `user_functional_areas`
on `functional_areas`.`id` = `user_functional_areas`.`functional_area_id`
where `user_functional_areas`.`user_id` in (2, 6, 7)
但实际上 6 和 7 是业务 id 而不是用户只有 2 是用户 id,其中一个查询应该使用business_functional_areas
而不是user_functional_areas
。 再发现一件事,结果中所有项目都在App\User
model 中,其类似的businesses
也为用户 object。
简而言之,目前您无法使用Eloquent Eager Loading
with Unions
来实现它。 Laravel 尚不支持此功能。 他们作为Non-Fix
问题关闭的其中一种情况是Union with Eloquent fail...。
Reason : While calling UNION
function only the first model( user
) is considered main model and model type of result set of other model( Business
) passed as argument will be converted to the main one( USER
) only and the main model relationship is called在所有记录上(不是所需的记录)。
由于上述问题,仅在结果集的每条记录上调用user
model 的关系。 所以即使business_id = 1,user_id = 1 的functional_area 也会被获取。
您可以从下面的文件和 function 中调试更多信息。
File:
<your_laravel_project>\vendor\laravel\framework\src\Illuminate\Database\Query\Builder.php
Function: get
替代解决方案您可以按原样获取两个结果集,然后在使用 php 获取数据后将它们合并。
public function usersAndOrganizations()
{
$users = $this->users()->get();
$organizations = $this->organizations()->get();
$invitees = $users->toBase()->merge($organizations->toBase())->toArray();
dd($invitees);
}
目前唯一的方法是使用map
。
public function usersAndOrganizations()
{
$users = $this->users();
$organizations = $this->organizations();
$invitees = $users->union($organizations)->paginate(10);
$invitees = $this->getRelatedData($invitees);
return response()->json($invitees);
}
private function getRelatedData($invitees)
{
$invitees->map(function($object) use($functionalAreaName) {
if($object->type == 'business') {
$relationName = 'businesses';
$relationKey = 'business_id';
$attachableType = Business::MORPHABLE_TYPE;
}
if($object->type == 'freelancer') {
$relationName = 'users';
$relationKey = 'user_id';
$attachableType = User::MORPHABLE_TYPE;
}
$functionalAreas = FunctionalArea::whereHas($relationName, function($q) use ($object, $relationKey){
$q->where($relationKey, $object->id);
})->get([$functionalAreaName.' As name', 'id']);
$object->functional_areas = $functionalAreas->toArray();
});
return $invitees;
}
并从你的函数中删除with
并在你得到分页结果后调用它。
您不能使用联合连接不兼容的查询。 请参阅工会。
您的users()
方法返回User
实体的 eloquent 构建器。 并且organizations()
返回Business
实体的构建器。
因此,一次查询对 select 用户和组织不正确。
正确的查询是这样的:
SELECT City FROM Customers
UNION
SELECT City FROM Suppliers
ORDER BY City;
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