有没有更优雅的方法可以使用 system.text.json 从 JSON object 获得特定值

Question

考虑这个 Json object：

{
    "main": {
        "2058": {
            "id": "2058",
            "name": "foo",
            "attrib1": "17",
            "domain": "somewhere.net",
            "enabled": "1",
            "permissions": [
                "admin",
                "user",
                "guest",
                "vpn",
                "power"
            ]
        }
    },
    "validate": {
        "2058": {
            "id": "2058",
            "name": "foo",
            "attrib1": "17",
            "domain": "somewhere.net",
            "enabled": "1",
            "permissions": [
                "admin",
                "user",
                "guest",
                "vpn",
                "power"
            ]
        }
    },
    "result": "ok"
}

在“启用”和“权限”之间，我遗漏了数百对。 “验证”部分是“主要”的精确副本，“结果”是结果。

我想从主要部分获得 2 个特定值。 “id”和“域”。 我使用下面的代码来做到这一点。

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text.Json;

namespace JsonParse
{
    class Program
    {
        static void Main()
        {
            string json = "{" +
                "\"main\":{" +
                    "\"2058\":{" +
                        "\"id\":\"2058\"," +
                        "\"name\":\"foo\"," +
                        "\"attrib1\":\"17\"," +
                        "\"domain\":\"somewhere.net\"," +
                        "\"enabled\":\"1\"," +
                        "\"permissions\":[\"admin\",\"user\",\"guest\",\"vpn\",\"power\"]" +
                    "}" +
                "}," +
                "\"validate\":{" +
                    "\"2058\":{" +
                        "\"id\":\"2058\"," +
                        "\"name\":\"foo\"," +
                        "\"attrib1\":\"17\"," +
                        "\"domain\":\"somewhere.net\"," +
                        "\"enabled\":\"1\"," +
                        "\"permissions\":[\"admin\",\"user\",\"guest\",\"vpn\",\"power\"]" +
                    "}" +
                "}," +
                "\"result\":\"ok\"" +
            "}";

            foreach (KeyValuePair<string, object> item in JsonSerializer.Deserialize<Dictionary<string, object>>(json))
            {
                if (item.Key == "main")
                {
                    Dictionary<string, object> pairs = JsonSerializer.Deserialize<Dictionary<string, object>>(item.Value.ToString());
                    Dictionary<string, object> pairs1 = JsonSerializer.Deserialize<Dictionary<string, object>>(pairs.First().Value.ToString());
                    foreach (KeyValuePair<string, object> valuePair in pairs1)
                    {
                        if (valuePair.Key == "id" || valuePair.Key == "domain")
                        {
                            Console.WriteLine("Key: " + valuePair.Key + "\nValue: " + valuePair.Value);
                        }
                    }
                }
            }
        }
    }
}

由此，我得到“2058”和“somewhere.net”，但是有没有更优雅的方式来获取值而不是反序列化 3 次？

Answer 1

如果您使用System.Text.Json API，则可以先将 JSON 解析为JsonDocument ，然后枚举其属性。 先获取main object，然后将其子属性展平，通过id和domain找到需要的值

using var document = JsonDocument.Parse(jsonString);

var main = document.RootElement.EnumerateObject().FirstOrDefault(p => p.Name == "main");
var properties = main.Value.EnumerateObject().SelectMany(p => p.Value.EnumerateObject()).ToList();
var id = properties.FirstOrDefault(p => p.Name == "id").Value.GetString();
var domain = properties.FirstOrDefault(p => p.Name == "domain").Value.GetString();

Answer 2

如果您只需要main属性，您可以通过 Newtonsoft Json.NET 使用json 路径到 select 所有“电源”：

var pairs = JObject.Parse(js).SelectTokens("$.main.*")
    .Select(j => (id:j["id"],domain: j["domain"]))
    .ToList();

或者只是反序列化为相应的结构（使用System.Text.Json或 Newtonsoft）：

class MyClass
{
    public Dictionary<string, InnerClass> main { get; set; }
}

class InnerClass
{
    public string id { get; set; }
    public string domain { get; set; }
}

ICollection<InnerClass> mains= JsonSerializer.Deserialize<MyClass>(js).main.Values; // System.Text.Json