[英]How to loop through the properties of anonymous type in a list
如果我有以下 LINQ 查询:
var outstandingDataTotalData = from t1 in dtTotal.AsEnumerable()
join t2 in dtOutstandingData.AsEnumerable() on
new
{
priv_code = t1["priv_code"],
pri_ded = t1["pri_ded"].ToString().Trim()
} equals
new
{
priv_code = t2["priv_code"],
pri_ded = t2["pri_ded"].ToString().Trim()
}
into ps
from t2 in ps.DefaultIfEmpty()
select new
{
adjustment_value = t2 == null ? string.Empty : t2["adjustment_value"].ToString(),
amount_outstanding = t2 == null ? string.Empty : t2["amount_outstanding"].ToString(),
amount_outstanding_priv = t2 == null ? string.Empty : t2["amount_outstanding_priv"].ToString(),
amount_outstanding_ded = t2 == null ? string.Empty : t2["amount_outstanding_ded"].ToString(),
diff_outstanding = t2 == null ? string.Empty : t2["diff_outstanding"].ToString(),
exchange_rate = t2 == null ? string.Empty : t2["exchange_rate"].ToString(),
SalYear = t2 == null ? string.Empty : t2["sal_year"].ToString(),
SalMonth = t2 == null ? string.Empty : t2["sal_mon"].ToString()
};
现在outstandingDataTotalData
是一个匿名类型的列表。 我有以下 class:
public class AdjustmentTotal
{
public string SalYear { get; set; }
public string SalMonth { get; set; }
public string Value { get; set; }
}
如何遍历outstandingDataTotalData
属性以填充List<AdjustmentTotal>
,如下例所示:
如果outstandingDataTotalData
总数据的结果集 =
[0]{ adjustment_value = "100.00", amount_outstanding = "80.00", amount_outstanding_priv = "60.00", amount_outstanding_ded = "30.52", diff_outstanding = "0.36", exchange_rate = "", SalYear = "2018", SalMonth = "1" }
[1]{ adjustment_value = "1500.00", amount_outstanding = "5040.00", amount_outstanding_priv = "", amount_outstanding_ded = "", diff_outstanding = "0.36", exchange_rate = "", SalYear = "2018", SalMonth = "1" }
我希望List<AdjustmentTotal>
的结果集为:
2018 1 100.00
2018 1 1500.00
2018 1 80.00
2018 1 5040.00
2018 1 60.00
2018 1
2018 1 30.52
2018 1
2018 1 0.36
2018 1 0.36
2018 1
2018 1
outstandingDataTotalData.Select(s => new AdjustmentTotal {
SalYear = s.SalYear,
SalMonth = s.SalMonth,
Value = s.adjustment_value
}).ToList();
让您的生活变得轻松,不要提取到单独的属性。 将提取物设为数组:
select new {
someArray = new[]{
t2["adjustment_value"].ToString(),
t2["amount_outstanding"].ToString(),
t2["amount_outstanding_priv"].ToString(),
t2["amount_outstanding_ded"].ToString(),
...
},
SalYear = ...,
}
所以你最终得到一个 object 有 3 个属性,两个字符串 SalXxx 和一个字符串数组(其他值)。 字符串数组意味着您可以使用 LINQ SelectMany将其展平。 您将在 msdn 示例中看到,他们的所有者拥有宠物列表(宠物数量可变,但您的值是固定数量),并且在 selectmany 之后,它被展平为所有者重复且只有一只宠物的列表。 您的小写值是宠物,SalXxx 值是所有者
获得有效查询后,您实际上可以将其集成到第一个查询中。
抱歉没有发布一个完整的例子(为了清楚起见,我跳过了 null 检查)——代码很难在手机上使用
编辑:
所以,你说你想要特定顺序的结果。 Select 和 SelectMany 都有一个版本,它们将提供项目的索引,我们可以使用它..因为您基本上想要拥有这些对象:
var obj = new [] {
new { SalYear = 2018, SalMonth = 1, C = new[] { "av1", "ao1", "aop1", "aod1" } },
new { SalYear = 2018, SalMonth = 2, C = new[] { "av2", "ao2", "aop2", "aod2" } }
};
就像av1, av2, ao1, ao2..
所以我们要先按内部数组的索引对结果进行排序,然后再按外部数组的索引
我们使用 SelectMany 挖掘内部数组,然后为内部数组中的每个项目创建一个新的 object ,其中包含数据和索引(内部和外部):
obj.SelectMany((theOuter, outerIdx) =>
theOuter.C.Select((theInner, innerIdx) =>
new {
SalYear = theOuter.SalYear,
SalMonth = theOuter.SalMonth,
DataItem = theInner,
OuterIdx = outerIdx,
InnerIdx = innerIdx
}
)
).OrderBy(newObj => newObj.InnerIdx).ThenBy(newObj => newObj.OuterIdx)
您可能会发现您不需要 ThenBy; 按 InnerIdx 排序会留下一个平局(我列表中的每个 InnerIdx 都表示两次 - 有两个 innerIdx=0 等),linq 中的东西尽可能地排序 - 因为它们已经按 OuterIdx 排序了(当他们去的时候进入查询)它们应该在与 InnerIdx 绑定后保持按 OuterIdx 排序。如果这是有道理的。 腰带和牙套!
使用 eum:
class Program
{
static void Main(string[] args)
{
List<AdjustmentTotal> totals = new List<AdjustmentTotal>();
for (int i = 0; i < (int)VALUE.END; i++)
{
foreach (var data in outstandingDataTotalData)
{
AdjustmentTotal total = new AdjustmentTotal();
totals.Add(total);
total.SalMonth = data.SalMonth;
total.SalYear = data.SalYear;
total._Type = (VALUE)i;
switch ((VALUE)i)
{
case VALUE.adjustment_value :
total.Value = data.adjustment_value;
break;
case VALUE.amount_outstanding:
total.Value = data.amount_outstanding;
break;
case VALUE.amount_outstanding_ded:
total.Value = data.mount_outstanding_ded;
break;
case VALUE.amount_outstanding_priv:
total.Value = data.amount_outstanding_priv;
break;
case VALUE.diff_outstanding:
total.Value = data.diff_outstanding;
break;
case VALUE.exchange_rate:
total.Value = data.exchange_rate;
break;
}
}
}
}
}
public enum VALUE
{
adjustment_value = 0,
amount_outstanding = 1,
amount_outstanding_priv = 2,
amount_outstanding_ded = 3,
diff_outstanding = 4,
exchange_rate = 5,
END = 6
}
public class AdjustmentTotal
{
public string SalYear { get; set; }
public string SalMonth { get; set; }
public string Value { get; set; }
public VALUE _Type { get; set; }
}
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