从当前周获取某一天，然后查询该日期

Question

我试图从本周的星期一到星期五获取日期。 然后使用这些日期查询我的 mysql 数据库。 但是我当前的代码不起作用。

$monday = date("Y-m-d",strtotime('next monday', strtotime('previous sunday')));

$sql = 
'SELECT *
FROM customers, jobs
WHERE customers.customerid = jobs.customerid AND duedate = "$monday" AND (jobs.status IS NULL OR jobs.status = "2" OR jobs.status = "3" OR jobs.status = "1" OR jobs.status = "5") AND (jobs.jobtype = "a" OR jobs.jobtype = "A" OR jobs.jobtype = "m" OR jobs.jobtype = "M")
ORDER BY duedate, jobtype';

我也尝试过使用此代码

$monday = date( 'Y-m-d', strtotime( 'monday this week' ) );

两种方式都没有显示任何结果。

Answer 1

您也可以使用 dayoftweek()

星期一 = 2

    SELECT *
    FROM customers, jobs
    WHERE customers.customerid = jobs.customerid 
    AND DAYOFWEEK(duedate) =  2 
    AND (jobs.status IS NULL OR jobs.status = "2" 
        OR jobs.status = "3" 
        OR jobs.status = "1" 
        OR jobs.status = "5") 
    AND (jobs.jobtype = "a"
     OR jobs.jobtype = "A" 
     OR jobs.jobtype = "m" 
     OR jobs.jobtype = "M")
    ORDER BY duedate, jobtype

Answer 2

我找到了解决方案。

这一切都在 sql 查询中完成。

                        $sql = 
                        'SELECT *
                        FROM customers, jobs
                        WHERE customers.customerid = jobs.customerid AND DAYOFWEEK(duedate) =  3 AND YEARWEEK(duedate) = YEARWEEK(NOW())
                        AND (jobs.status IS NULL OR jobs.status = "2" OR jobs.status = "3" OR jobs.status = "1" OR jobs.status = "5") 
                        AND (jobs.jobtype = "a" OR jobs.jobtype = "A" OR jobs.jobtype = "m" OR jobs.jobtype = "M")
                        ORDER BY duedate, jobtype';