数组推送方法行为异常 javascript

Question

我有一个 function 将数组作为参数

[["52", ["41", "43", "61", "63"]], ["54", ["43", "45", "63", "65"]]]

“52”是我的硬币， ["41", "43", "61", "63"]是硬币“52”的可能移动位置。 这同样适用于 "54" 和["43", "45", "63", "65"] 。

在我的情况下cell.innerHTML == ''用于位置“41”、“43”、“45”

function 行为正确，直到freeLocations.push(freeLocation); 它的输出在哪里

["52", "41"], ["52", "43"], ["54", "43"] and ["54", "45"].

但是，allFreePostions.push(freeLocations) 仅输出 3 个 arrays：["52", "41"], ["52", "43"] 和 ["54", "45"]。 ["54", "43"] 丢失。

奇怪的是，如果我只是为了调试而编辑freeLocations.push(freeLocation, j) ，丢失的数组会显示在allFreePostions.push(freeLocations)中。

我在这里错过了什么吗？

 function checkFreeLocations(coins){ let allFreePostions = []; let dangerPosition = []; for (let i = 0; i < coins.length; i++){ coin = coins[i][0]; positions = coins[i][1]; for (let j = 0; j < positions.length; j++){ let freeLocations = []; let cell = document.getElementById(positions[j]); if (cell.innerHTML == ''){ freeLocation = positions[j]; freeLocations.push(coin); freeLocations.push(freeLocation); allFreePostions.push(freeLocations); } } } } checkFreeLocations([["52", ["41", "43", "61", "63"]], ["54", ["43", "45", "63", "65"]]])

Answer 1

看起来您的 HTML 中有非唯一 ID，这给您带来了麻烦。

我相信 ["54", "43"] 未显示的原因是因为您查看元素是否为空：

 let cell = document.getElementById(positions[j]); if (cell.innerHTML == ''){ freeLocation = positions[j]; freeLocations.push(coin); freeLocations.push(freeLocation); allFreePostions.push(freeLocations); }

这种情况可能是您之前已经用 ['52', '43'] 填充了该元素。 但请添加您的 HTML 以便于掌握。

Answer 2

我不知道这是否有帮助，但这就是我更改硬币内所有数据的方式。

 let coins = [ ["52", ["41", "43", "61", "63"]], ["54", ["43", "45", "63", "65"]] ]; console.log(coins); function checkFreeLocations(coins){ let allFreePostions = []; for (let i = 0; i < coins.length; i++){ let freeLocations = []; freeLocations.push(i); let freeLocation = []; for (let j = 0; j < coins[i][1].length; j++){ let change = 'X'; freeLocation.push(change); } freeLocations.push(freeLocation); allFreePostions.push(freeLocations); } return allFreePostions; } console.log(checkFreeLocations(coins));