拥有模式中的 OneToOne 关系休眠+spring-data-jpa null 值

Question

我是 Hibernate 和 JPA 的新手（我主要使用 JDBC 进行存储过程集成。）。 我创建了两个具有 OneToOne 关系的实体 User 和 UserPassword。 我试图在两个表（MySQL DB）中存储值，但 UserPassword 表的 UserId（foreign_key）列存储 null 而密码被存储。 请纠正我在以下代码中的错误：

@Entity
@Table(name = "User")
public class User implements Serializable{


    private static final long serialVersionUID = -3366411610525655274L;
    
    @Column(name = "UserId", nullable = false,unique = true)
    @GenericGenerator(name = "uuid2", strategy = "uuid2")
    @GeneratedValue(generator = "uuid2")
    @Id
    @Type(type="uuid-char")
    private UUID userId;
    
    @Embedded
    private Name name; 
    
    @Column(name = "DateOfBirth", nullable = false)
    private Date dob;
    
    @OneToOne(mappedBy="user", cascade=CascadeType.ALL)
    private Password password;

    public Password getPassword() {
        return password;
    }

    public void setPassword(Password password) {
        this.password = password;
    }

    public UUID getUserId() {
        return userId;
    }

    public void setUserId(UUID userId) {
        this.userId = userId;
    }

    public Name getName() {
        return name;
    }

    public void setName(Name name) {
        this.name = name;
    }

    public Date getDob() {
        return dob;
    }

    public void setDob(Date dob) {
        this.dob = dob;
    }
    
}

和

@Entity
@Table(name= "UserPassword")
public class Password implements Serializable{

    private static final long serialVersionUID = -8990341903052492314L;

    @Id
    @GeneratedValue(strategy=GenerationType.IDENTITY)
    @Column(name="PasswordId")
    private Long Id;
    
    @Column(name="Password")
    private String password;
    
    @OneToOne(cascade=CascadeType.ALL,fetch=FetchType.LAZY)
    @JoinColumn(name="UserId", referencedColumnName="UserId")
    private User user;

    public Long getId() {
        return Id;
    }

    public void setId(Long id) {
        Id = id;
    }

    public String getPassword() {
        return password;
    }

    public void setPassword(String password) {
        this.password = password;
    }
    
}

这些是我的 JPA 存储库：

public interface UserRepository extends JpaRepository<User, UUID>{

}

和

public interface PasswordRepository extends JpaRepository<Password, Long>{

}

和服务层代码将实体保存在数据库中：

public void insertUsers(List<User> users) {
        
        List<com.poc.entity.User> usersData = ObjectMapperUtils.mapAll(users, com.poc.entity.User.class);
        
        userRepository.saveAll(usersData);
    }

另外，请帮助我为这项工作采取适当的设计方法。

Answer 1

它通过对服务层逻辑进行小的修改来工作。

 public void insertUsers(List<User> users) {
        
        List<com.poc.entity.User> usersData = ObjectMapperUtils.mapAll(users, com.poc.entity.User.class);
            
        usersData = usersData.stream().map(user->mapUserPassWordEntity(user)).collect(Collectors.toList());
        
        userRepository.saveAll(usersData);
    }

    private com.poc.entity.User mapUserPassWordEntity(com.poc.entity.User user) {
        Password password = new Password();
        password.setPassword(user.getPassword().getPassword());
        //set parent reference to child
        password.setUser(user);
        // set child reference to parent
        user.setPassword(password);
        return user;
    }

不过，我会很感激更多关于更好方法的建议。