[英]I want an SQLquery to find highest MonthlyActiveUsers per month such that each month is aggregated to just ONE row
在聚合了 MONTH 列的数据库中查找每个日历月的每月最高活跃用户数,以便每个月仅聚合到一行
SELECT
MONTH([OrderDate]) AS Month,
[Name] AS Country,
COUNT([CustomerID]) AS 'Number of Customers Per Month'
FROM
[Sales].[SalesOrderHeader] AS A
LEFT JOIN
[Sales].[SalesOrderDetail] AS B ON A.SalesOrderID = B.SalesOrderID
LEFT JOIN
[Sales].[SalesTerritory] AS C ON A.TerritoryID = C.TerritoryID
GROUP BY
MONTH([OrderDate]), [Name]
ORDER BY
3 DESC
最简单的方法在ORDER BY
中使用TOP (1) WITH TIES
和ROW_NUMBER()
:
SELECT TOP (1) WITH TIES MONTH([OrderDate]) AS Month, [Name] AS Country,
COUNT(*) AS [Number of Customers Per Month]
FROM [Sales].[SalesOrderHeader] soh LEFT JOIN
[Sales].[SalesOrderDetail] sod
ON soh.SalesOrderID = sod.SalesOrderID LEFT JOIN
[Sales].[SalesTerritory] st
ON soh.TerritoryID = st.TerritoryID
GROUP BY MONTH([OrderDate]), [Name]
ORDER BY ROW_NUMBER() OVER (PARTITION BY MONTH([OrderDate]) ORDER BY COUNT(*) DESC);
笔记:
a
/ b
/ c
是任意的。 使用表格缩写!
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