Java - 每 n 个字符添加一个新行，而不拆分单词

Question

所以我一直试图让用户输入的字符串每 n 个字符有一个换行符。 我发现基本上是我写的，我对 Java 很陌生（Python 有一个 function to.fill，但我无法在 Java 中解决这个问题）并且似乎无法让我的字符串不把单词分开。 我将程序设置为每 10 个字符“\n”，但它会在中间打断一些单词......如果它不符合 10 个字符的限制，我希望它接受该单词并将其移动到下一行。

import java.util.Scanner;

public class Wrap {
    public static void main(String[] args) {

        Scanner scan = new Scanner(System.in);
        System.out.println("Enter your text: ");
        String newString = scan.nextLine();
        newString = newString.replaceAll(".{10}",  "$0\n");
        System.out.println(newString);

/** 第二种方法，还是截断单词...

    StringBuilder builtString = new StringBuilder();
        int i = 0;
        while ((i= builtString.indexOf(newString, i + 10)) != -1) {
            builtString.replace(i, i+1, "\n");
        
        }
        System.out.println(builtString);
        */
    
        System.out.println(newString);
    }
}

单词被分开了:(

Output：

This is a 
test and i
t doesnt s
eem to be 
working pr
operly.

In Python I got this output which was what I wanted, but Java doesn't seem to have a textwrap function that's "easy" like Python's or at least I haven't figured it out yet. 所需 Output

Answer 1

public static void main(String[] args) {
    String text = "This is a test and it doesnt seem to be working properly.";
    String[] works = text.split(" "); // get list of works
    StringBuilder line = new StringBuilder();
    StringBuilder result = new StringBuilder();
    for (String work : works) {
        if (line.length() + work.length() > 10) { //add line to result if it full
            result.append(line).append("\n");
            line = new StringBuilder(); //reset line is empty
        }
        line.append(work).append(" ");
    }
    result.append(line);
    System.out.println(result.toString());
}