[英]Filter an object containing a key that contains an array of objects using an array of strings
[英]filter array of object which contains array of objects by an array
我正在尝试过滤数组,但无法成功过滤 object 中的数组
我将举一个数组的例子:
const data = [
{
path: 'data1',
main: [
{
path: 'mainData11'
},
{
path: 'mainData12'
}
]
},
{
path: 'data2',
main: [
{
path: 'mainData21'
},
{
path: 'mainData22'
}
]
}
];
const filterArray = ['data1', 'mainData12'];
预期结果
const data = [
{
path: 'data1'
main: [
{
path: 'mainData12'
}
]
}
]
我试过的
data.filter(el => filterArray.includes(el.path))
我没有成功过滤object里面的main
...
我该怎么做?
谢谢!
**更新——当前解决方案
data.reduce((results, item) => {
if(filterArray.some(f => item.path === f)){
results.push(
{
...item,
path: item.path,
main: item.main.filter(i => filterArray.some(f => i.path === f))
}
)
};
return results;
}, []);
您可以通过重建 object 来解决它:
const data = [{ path: 'data1', main: [{ path: 'mainData11', }, { path: 'mainData12', }, ], }, { path: 'data2', main: [{ path: 'mainData21', }, { path: 'mainData22', }, ], }, ]; const filterArray = ['data1', 'mainData12']; const filteredData = data.filter(entry => entry.path === filterArray[0]).map(entry => ({ path: entry.path, main: entry.main.filter(x => x.path === filterArray[1]), })).filter(entry => entry.main.length); console.log(filteredData);
如果您使用 reduce,这可以一步完成
const data = [ { path: 'data1', main: [ { path: 'mainData11' }, { path: 'mainData12' } ] }, { path: 'data2', main: [ { path: 'mainData21' }, { path: 'mainData22' } ] } ]; const filterArray = ['data1', 'mainData12']; const results = data.reduce((results, item) => { if (filterArray.some(f => item.path === f) && item.main.some(i => filterArray.some(f => i.path === f))) { results.push( { path: item.path, main: item.main.filter(i => filterArray.some(f => i.path === f)) } ); } return results; }, []); console.log(results)
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