我怎样才能使分页？

Question

我想从数据库中对我的图片进行分页。 我试过的任何东西都不起作用，我不知道该怎么办。 有人可以为我解释一下吗？ 看了很多教程，仍然找不到解决方案（我是初学者）。

<?php
// Connect to MySQL
$pdo = pdo_connect_mysql();
// MySQL query that selects all the images
$stmt = $pdo->query('SELECT * FROM images ORDER BY uploaded_date DESC');
$images = $stmt->fetchAll(PDO::FETCH_ASSOC);
?>


    <div class="content home">
    <h2>Gallery</h2>
    <p>Welcome to the gallery page, you can view the list of images below.</p>

    <div class="images">
        <?php foreach ($images as $image): ?>
        <?php if (file_exists($image['path'])): ?>
        <a href="#">
            <img src="<?=$image['path']?>" alt="<?=$image['description']?>" data-id="<?=$image['id']?>" data-title="<?=$image['title']?>" width="300" height="200">
            <span><?=$image['description']?></span>
        </a>
        <?php endif; ?>
        <?php endforeach; ?>
    </div>


    <div class="container">
  <ul class="pagination">
    <li class="page-item"><a class="page-link" href="#">Previous</a></li>
    <li class="page-item"><a class="page-link" href="#">1</a></li>
    <li class="page-item"><a class="page-link" href="#">2</a></li>
    <li class="page-item"><a class="page-link" href="#">3</a></li>
    <li class="page-item"><a class="page-link" href="#">Next</a></li>
  </ul>
</div>


</div>

Answer 1

LIMIT 和 OFFSET 的样子

SELECT * FROM images ORDER BY uploaded_date DESC LIMIT 5 OFFSET 10

OFFSET 值将具有页面的效果。 OFFSET 0 是第 1 页 OFFSET 5 是第 2 页 OFFSET 10 是第 3 页等.....

Answer 2

php 中的分页

<?php  
    $limit = 3;  //set  Number of entries to show in a page.
    // Look for a GET variable page if not found default is 1.        
    if (isset($_GET["page"])) {    
    $page  = $_GET["page"];    
    }    
    else { $page=1;    
    } 
    //determine the sql LIMIT starting number for the results on the displaying page  
    $page_index = ($page-1) * $limit;      // 0

    $All_Users=mysqli_query($con,"select * from users limit $page_index, $limit");
    while($row=mysqli_fetch_array($All_Users))
    {
        //show  data in table or where you want..
    }
    $all_data=mysqli_query($con,"select count(*) from users");
    $user_count = mysqli_fetch_row($all_data);   //total count 9  
    $total_records = $user_count[0];   //9
    $total_pages = ceil($total_records / $limit);    // 9/3=  3
    if($page >= 2){
        echo "<a href='blog.php?page=".($page-1)."' class='btn customBtn2'>Previous</a>";
      }
    
    if($page<$total_pages) {
        echo "<a href='blog.php?page=".($page+1)."' class='btn customBtn2'>NEXT</a>";   
    }       
?>