[英]How to use a calculated value in Oracle SQL count
在我看来,我有一个名为 BIRTH_DATE 的列。 我想使用该列和今天的日期计算年龄,并计算年龄范围内的员工人数。 例如:40 到 49 之间的员工等。
也欢迎使用普通 SQL 语句中的其他答案。
我的代码如下所示:
$count = StaffEmploymentListView::find()
->select([
'COUNT(*) AS TEACHING_COUNT',
'BIRTH_DATE' => 'BIRTH_DATE'
])
->where(['GENDER' => 'MALE', 'JOB_CADRE' => 'ACADEMIC'])
->andFilterHaving(['>=', "TRUNC(months_between(sysdate, BIRTH_DATE) / 12)", 40])
->andFilterHaving(['<', "TRUNC(months_between(sysdate, BIRTH_DATE) / 12)", 70])
->groupBy(['BIRTH_DATE'])
->all();
我正在计算年龄,如下所示:
TRUNC(months_between(sysdate, BIRTH_DATE) / 12)
执行此操作后,如果我尝试访问 model 中的 TEACHING_COUNT 变量,则它是 null。
我将回答 SQL 示例。 我不知道上面的代码在 PHP 中是如何工作的,但是由于按“BIRTH_DATE”分组,每个年龄你会得到不止一行,并且在返回时可能会出现问题。
如果我理解您需要的是 SUM over count(*) 但如果查询没有在任何地方重复使用并且您不需要 count perbirth_date 您只需从查询构造中删除 group by。
见下文,
create table StaffEmployment
( name varchar2(100)
, gender varchar2(10)
, job_cadre varchar2(50)
, birth_date date
);
----------------------------------------------------------------------
insert all
into staffemployment(name,gender,job_cadre,birth_date)
values('A','M','Acdemic',sysdate-(45*365))
into staffemployment(name,gender,job_cadre,birth_date)
values('B','M','Acdemic',sysdate-(45*365))
into staffemployment(name,gender,job_cadre,birth_date)
values('C','F','Acdemic',sysdate-(70*365))
into staffemployment(name,gender,job_cadre,birth_date)
values('D','F','Acdemic',sysdate-(10*365))
SELECT * FROM dual;
----------------------------------------------------------------------
select t.*,TRUNC(months_between(sysdate, BIRTH_DATE) / 12) age
from StaffEmployment t;
----------------------------------------------------------------------
NAME GENDER JOB_CADRE BIRTH_DAT AGE
----- ---------- ---------- --------- ----------
A M Acdemic 13-AUG-75 44
B M Acdemic 13-AUG-75 44
C F Acdemic 19-AUG-50 69
D F Acdemic 04-AUG-10 9
----------------------------------------------------------------------
select BIRTH_DATE,count(*)
from StaffEmployment t
where TRUNC(months_between(sysdate, BIRTH_DATE) / 12) >= 40
and TRUNC(months_between(sysdate, BIRTH_DATE) / 12) < 70
group by BIRTH_DATE;
----------------------------------------------------------------------
BIRTH_DAT COUNT(*)
--------- ----------
13-AUG-75 2
19-AUG-50 1
----------------------------------------------------------------------
And if we do a sum you get the actual count over all rows
----------------------------------------------------------------------
select SUM(count(*)) teacing_count
from StaffEmployment t
where TRUNC(months_between(sysdate, BIRTH_DATE) / 12) >= 40
and TRUNC(months_between(sysdate, BIRTH_DATE) / 12) < 70
group by BIRTH_DATE;
----------------------------------------------------------------------
TEACING_COUNT
-------------
6
您也可以计算一个年龄段之间的记录数,而无需编写任何SQL
。
$from = date('Y-m-d', strtotime('-49 years'));
$to = date('Y-m-d', strtotime('-40 years'));
$query = StaffEmploymentListView::find()
->where(['>=', 'BIRTH_DATE', $from])
->andWhere(['<=', 'BIRTH_DATE', $to]);
// You can get the count
$count = $query->count();
// Or use the query to display the results
echo Html::tag('h1',
'Found ' . $query->count() . ' clients born between ' .
Yii::$app->formatter->asDate($from) . ' and ' .
Yii::$app->formatter->asDate($to)
);
$dataProvider = new ActiveDataProvider([
'query' => $query
]);
echo GridView::widget([
'dataProvider' => $dataProvider,
'columns' => [
'name',
'BIRTH_DATE:date',
[
'attribute' => 'BIRTH_DATE',
'value' => static function($model) {
return floor((time() - strtotime($model->BIRTH_DATE)) / 31556926);
},
'label' => 'Age'
]
]
]);
由于您已经在使用yii ,因此直接使用它的方法似乎很有意义。 在这种情况下, count()方法。
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