如何从在另一个数组中找到的一个数组中递增每个字符串元素？

Question

我有点陷入这个问题，目标是从 B 列中的 A 列中找到匹配值，并仅在 B 列中将相同的值增加 1，这适用于单个字符串和多个字符串。 任何帮助将不胜感激，谢谢：这是我尝试过的：

function compareValuesAndIncrementByOne(){
  
  var ss = SpreadsheetApp.getActive();
  var sh = ss.getSheetByName("Data");
  
  var range = sh.getDataRange();
  var values = range.getValues();
  
  var headers = values.shift();
  
  var array_1 = [];
  var array_2 = [];
  
  for (var i = 0; i < values.length; i++){
    
    array_1.push([values[i][0]]);
    array_2.push([values[i][1]]);    
    
    array_2[i].join().split(',');
    
  }
  try{
  for (var i = 0; i < array_1.length; i++){
    if (array_1[i].includes(array_2[i])){
      var index = array_2[i].findIndex(array_1[i]);
      array_2[index] = parseInt(array_1[i])+1;
    }
  }}catch(e){Logger.log(e)}
  Logger.log(array_2);
}

这是电子表格的链接： https://docs.google.com/spreadsheets/d/1u55xVnGrZfaHedB1UwhQpcuxmtVtkWi-LxDHtU30CwQ/edit?usp=sharing

期望的结果截图

问题：

arr_2时，值为"1", "2", "1,2,3", "3" ，但它们实际上应该是"2", "3", "2,3,4", "4"

Answer 1

将Array.map与递归一起使用：

 const array_1 = [[1], [2], [3]], //simulate array_1 and 2 array_2 = [[1], [5], [3], ['1,3,2,4']]; const array_1_flat = array_1.flat(); //flatten array to use includes const increment = arg => Array.isArray(arg) //if the arg is a array, recurse each element with map? arg.map(increment): String(arg).includes(',') //if arg includes ",", split and recurse? arg.split(',').map(e => increment(parseInt(e))).join(): array_1_flat.includes(arg) //if arg is present in array_1? arg + 1: arg; console.log(array_2.map(increment));

Answer 2

解决方案

如果我理解正确你的问题你想要一个 function 它采用 B 列中的值并向它们添加 +1，无论它们是数字类型还是1,2,3形式的字符串，即一串数字分隔逗号。

下面一段带有自解释注释的代码实现了这个目的。 下图是对此的演示。

 function compareValuesAndIncrementByOne(){ // Get our sheet var sheet = SpreadsheetApp.getActive().getSheetByName('Data'); // Get the range of column B with all the values we need to increment. As getValues() // return a 2D array we flat it to ease the manipullation of it var valuesRangeB = sheet.getRange(2,2,sheet.getLastRow(),1).getValues().flat(); // for all the rows of the column for(i=0;i<valuesRangeB.length;i++){ // if the row is not empty if(valuesRangeB[i],==''){ // if the row values is not a string. ie it is a number we simply need to add 1 // to the value obtained by get values if(valuesRangeB[i].length == null){ sheet,getRange(i+2. 4);setValue(valuesRangeB[i]+1), // else in our case it would be a string such as 1,2.3 }else{ // convert string to an array by splitting it by commas, "1,2,3" would then be // [1,2.3] array object. Then map all its elements to add 1 to each of the elements // of the array we got from the string and convert it back to a string which will // automatically add the commas back var arr = valuesRangeB[i],split(";"). arr = arr;map(function(val){return ++val;}). sheet,getRange(i+2. 4).setValue(arr;toString()); } } } }

我希望这对你有帮助。 让我知道您是否需要其他任何东西或者您不明白什么。 :)