Java - 标准 API - 单向 OneToMany

Question

我正在尝试通过标准 API 从流程表中的人员那里获取许可证号。 基本上来自Process -> Person -> License

但是，Person 表与表 License 具有单向 OneToMany 关系。

所以我有以下实体：

@Entity
@Table(name = "Process")
public class Process {
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Integer id;
    
    @OneToOne(fetch = FetchType.EAGER)
    @JoinColumn(name = "person_id")
    Person person;
}

@Entity
@Table(name = "Person")
public class Person {
    @Id
    @Column(name = "id",columnDefinition="INTEGER")
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    Integer id;
    
    @OneToMany(fetch = FetchType.LAZY, mappedBy = "person")
    List<License> licenses;
}

@Entity
@Table(name = "License")
public class License {
    @Id
    @Column(name = "id",columnDefinition="INTEGER")
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    Integer id;
    
    @JoinColumn(name = "person_id")
    @ManyToOne(fetch = FetchType.LAZY)
    Person person;
    
    String licenseNumber;
}

在本机查询中，我想要完成的结果是：

  select lic.license_number, * from Process process
  left join Person p on process.person_id = p.id
  left join License lic on lic.person_id = p.id;

我试过加入：

final CriteriaBuilder builder = entityManager.getCriteriaBuilder();
final CriteriaQuery<Process> criteria = builder.createQuery(Process.class);
final Root<Process> rootSelect = criteria.from(Process.class);

//I don't really know how to join rootSelect (Process table), with License table... having the table Person in middle..
Join<Process, Person> personJoin = rootSelect.join("person");
Join<License, Person> licenseJoin = rootSelect.join("person");

并且还考虑使用子查询：

final CriteriaBuilder builder = entityManager.getCriteriaBuilder();
final CriteriaQuery<Process> criteria = builder.createQuery(Process.class);
final Root<Process> rootSelect = criteria.from(Process.class);

Subquery sub = criteria.subquery(String.class);
Root subRoot = sub.from(License.class);
//How to select just the field 'license_number' below?
sub.select(subRoot);
sub.where(builder.equal(rootSelect.get("person").get("id"), subRoot.get("person")));

最后，我将需要 license_number 用于过滤器（在哪里）。

考虑到我的根表是 Process，执行这种过滤器的最佳方法是什么？

Answer 1

严格来说，您不必使用许可证加入 Process 表，您必须将 Process 加入 Person 和 Person with License，如下所示：

Join<Process, Person> personJoin = rootSelect.join("person",JoinType.INNER);
Join<Person, License> licenseJoin = personJoin.join("licenses",JoinType.INNER);

建议使用元模型和实体，它们的连接如下（元模型由 EntityName_ 表示）：

Join<Process, Person> personJoin = rootSelect.join(Process_.person,JoinType.INNER);
Join<Person, License> licenseJoin = personJoin.join(Person_.licences,JoinType.INNER);

对我来说，最明显的好处是您可以自动完成元模型的属性，放置字符串会增加我们出错的机会。

我们添加过滤条件

cq.where(cb.equal(licenceseJoin.get("licenseNumber"),LICENSE_NUMBER));
//cq.where(cb.equal(licenceseJoin.get(License_.licenseNumber),LICENSE_NUMBER));