将 Symfony services.yaml 和 security.yaml 转换为 ZE1BFD762321E409CEE4AC0B6E 格式

Question

我想将我的所有配置文件从 YAML 转换为 PHP 格式。

问题

我有这个服务。yaml：

services:
    # default configuration for services in *this* file
    _defaults:
        autowire: true      # Automatically injects dependencies in your services.
        autoconfigure: true # Automatically registers your services as commands, event subscribers, etc.

    # makes classes in src/ available to be used as services
    # this creates a service per class whose id is the fully-qualified class name
    App\:
        resource: '../src/*'
        exclude: '../src/{DependencyInjection,Entity,Migrations,Tests,Kernel.php}'

    # controllers are imported separately to make sure services can be injected
    # as action arguments even if you don't extend any base controller class
    App\Controller\:
        resource: '../src/Controller'
        tags: ['controller.service_arguments']

    App\EventListener\ExceptionListener:
        tags:
            - { name: kernel.event_listener, event: kernel.exception }

我的安全.yaml

security:
    encoders:
        App\Entity\User:
            algorithm: auto
    providers:
        users:
            entity:
                class: 'App\Entity\User'
                property: 'username'

services.php 和 security.php 等效项应该是什么？ 我试过 services.php：

<?php

namespace Symfony\Component\DependencyInjection\Loader\Configurator;

use App\EventListener\ExceptionListener;

return function(ContainerConfigurator $configurator) {
    $services = $configurator->services()
        ->defaults()
        ->autowire()      // Automatically injects dependencies in your services.
        ->autoconfigure() // Automatically registers your services as commands, event subscribers, etc.
    ;

    // makes classes in src/ available to be used as services
    // this creates a service per class whose id is the fully-qualified class name
    $services->load('App\\', '../src/*')
        ->exclude('../src/{DependencyInjection,Entity,Tests,Kernel.php}');

    // ?????
    // How to get $container here?
    // ?????
    $container->register(ExceptionListener::class)
        ->addTag('kernel.event_listener', ['event' => 'kernel.exception'])
    ;
};

它对我不起作用......我不明白如何将 $container 注入这个文件

Answer 1

基本问题是文档中注册事件监听器的示例需要更新。 就像是：

# config\services.php
return function (ContainerConfigurator $configurator) {
    $services = $configurator->services()->defaults()
        ->autowire()
        ->autoconfigure();
    ...
    $services->set(ExceptionListener::class)
        ->tag('kernel.event_listener',['event' => KernelEvents::EXCEPTION]);

离题但使用事件订阅者将消除配置它的需要。

就安全配置文件而言，它只是一个大的 php 阵列。 您从文档中的示例开始，然后只是找出键的问题。 这是我认为涵盖您的问题的示例：

# config/packages/security.php

// Keeps IDE happy
/** @var ContainerBuilder $container */
$container = isset($container) ? $container : null;

$container->loadFromExtension('security', [

    'enable_authenticator_manager' => true, // 5.1 or later

    'encoders' => [
        User::class => [
            'algorithm' => 'auto',
            'cost' => 12,
        ]
    ],
    'providers' => [
        'user_provider' => [
            'entity' => [
                'class' => User::class,
            ],
        ],
    ],
    'firewalls' => [
        'dev' => [
            'pattern' => '^/(_(profiler|wdt)|css|images|js)/',
            'security' => false,
        ],
        'main' => [
            'lazy' => true,
            'provider' => 'user_provider',
            'guard' => [
                'authenticators' => [
                    UserLoginFormAuthenticator::class,
                ]
            ],
            'logout' => [
                'path'   => 'user_logout',
                'target' => 'home_index'
            ],
        ],
    ],
    // Don't want to go to far down this rabbit hole
    'access_control' => [
        ['path' => '^/admin',      'roles' => 'ROLE_ADMIN'],
        //['path' => '^/home',       'roles' => AccessListener::PUBLIC_ACCESS],
        ['path' => '^/user/login', 'roles' => AccessListener::PUBLIC_ACCESS],
    ],
]);