繁体   English   中英

根据字段值限制查询结果

[英]Limit query result based on field value

我有一个具有休闲结构的表account

| agg_type  | agg_id  | sequence | payload | is_snapshot | timestamp |
| "account" | "agg_1" | 1        | "..."   | false       | ...       |
| "account" | "agg_1" | 2        | "..."   | true        | ...       |
| "account" | "agg_1" | 3        | "..."   | false       | ...       |
| "account" | "agg_1" | 4        | "..."   | false       | ...       |
| "account" | "agg_1" | 5        | "..."   | false       | ...       |
| "account" | "agg_1" | 6        | "..."   | false       | ...       |
| "account" | "agg_1" | 7        | "..."   | true        | ...       |
| "account" | "agg_1" | 8        | "..."   | false       | ...       |

我需要编写一个查询,该查询将从特定聚合的最新快照开始从该表中检索所有行。 例如,在此表的情况下,查询将返回最后两行(序列 7 和 8)。

我认为查询将 go 类似于

SELECT * FROM account 
WHERE
  agg_type='account'
  AND agg_id='agg_1'
ORDER BY sequence ASC
LIMIT (???);

这是我不太确定如何实施的(???)部分。

观察:

  • 如果有任何帮助,我正在使用 Postgres。
  • (agg_type, agg_id, sequence) 组合是主键。

简单地说,我们可以只检索序列大于或等于快照的最高序列 id 的所有帐户

SELECT * FROM account a
WHERE
  a.agg_type='account'
  AND a.agg_id='agg_1' 
  AND a.sequence >= 
    (SELECT MAX(sequence) FROM account b WHERE a.agg_type = b.agg_type AND a.agg_id = b. agg_id AND b.is_snapshot = true)

如果您想全部完成,则将其编写为联接可能会更清楚:

SELECT a.* 
FROM 
  account a
  INNER JOIN
  (
    SELECT 
      agg_type, 
      agg_id, 
      MAX(sequence) as maxseq 
    FROM account b 
    GROUP BY agg_type, add_id
  ) maxes
  ON 
    a.agg_type = maxes.agg_type and
    maxes.agg_id = a.max_id and
    a.sequence >= maxes.maxseq

这并不是说我们不能用任何一种形式完成任何一项任务(并且内部 postgres 可能无论如何都会执行它们),但我一直认为使用连接作为“这里有 10000 行,我想要只有符合这 1000 行规定的标准的 2000 行”最清楚地被认为是连接在一起的数据块

WITH a AS ( SELECT *,row_number() over(partition BY a.agg_type,a.agg_id ORDER BY a."SEQUENCE" DESC) rnk FROM account a ) SELECT * FROM a WHERE a.rnk <= 2;

一个 window function 可以为所有(agg_type, agg_id)组合仅使用一种排序:

with mark as (
  select *, 
         bool_or(is_snapshot) over w as trail_true
    from account
  window w as (partition by agg_type, agg_id 
                   order by sequence
            rows between 1 following
                     and unbounded following)
)
select *
  from mark
 where not coalesce(trail_true, false)
 order by agg_type, agg_id, sequence

暂无
暂无

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM