如何在不重复的情况下用javascript中的对象替换对象数组

Question

let a = [{ name: "ben", age: 25 }, { name: "jeffrey", age: 10 },{ name: "daniel", age: 20 }]
let case1 = { name: "ben", age: 10 }
let case2={ name: "jack", age: 30 }

案例1：我希望结果是

[{ name: "ben", age: 10 }, { name: "jeffrey", age: 10 },{ name: "daniel", age: 20 }]

“ben”存在的地方，所以它将年龄替换为 10

案例2：我希望结果是

[{ name: "ben", age: 25 }, { name: "jeffrey", age: 10 },{ name: "daniel", age: 20 },{ name: "jack", age: 30 }]

其中“jack”不在数组中，因此它添加到数组中

如何编写执行此功能的函数

Answer 1

也可以用for循环来完成。

 function untitled(original, newObj) { for (let index = 0; index < original.length; index++) { if (original.name && newObj.name === a[index].name) { original[index] = {...newObj}; console.log(original); return; } } original.push(newObj); console.log(original); } let a = [{ name: "ben", age: 25 }, { name: "jeffrey", age: 10 },{ name: "daniel", age: 20 }] let case1 = { name: "ben", age: 10 } let case2 = { name: "jack", age: 30 } untitled(a, case1); untitled(a, case2);

Answer 2

你是Array.prototype.findIndex ( MDN ) 的一个很好的例子，它类似于Array.prototype.find但返回找到的索引而不是项目。

 let a = [{ name: "ben", age: 25 }, { name: "jeffrey", age: 10 },{ name: "daniel", age: 20 }] let case1 = { name: "ben", age: 10 } let case2 = { name: "jack", age: 30 } const arrayUpsert = function (array, object) { const objectIndex = array.findIndex(item => item.name == object.name) if (objectIndex == -1) { array.push(object) } else { array[objectIndex] = { ...array[objectIndex], ...object } } return array } console.log(arrayUpsert(a, case1)) console.log(arrayUpsert(a, case2)) /* [ { name: 'ben', age: 10 }, { name: 'jeffrey', age: 10 }, { name: 'daniel', age: 20 } ] [ { name: 'ben', age: 10 }, { name: 'jeffrey', age: 10 }, { name: 'daniel', age: 20 }, { name: 'jack', age: 30 } ] */

Answer 3

我在我的解决方案中使用 ramda 库：-

• 检查键是否存在于数组中的任何对象中
  idx = R.findIndex(R.propEq('name', 'ben'), a) . 如果idx<0那么我们可以直接推送对象，否则进入下一步。

• 我们有索引（idx），我们只需要做a[idx].age="--" 。