未在函数内执行的 JavaScript 代码

Question

为什么app.init()函数中的代码没有执行？

 (function () { console.log('loaded here'); function ready(callbackFunction){ if (document.readyState != 'loading') callbackFunction(event) else document.addEventListener("DOMContentLoaded", callbackFunction) } var app = function (options) { var app = this, version = 1.00; app.init = function () { console.log('not loaded here'); console.log(window); } app.init(); }; ready(event => { console.log('dom is loaded'); window.myApp = function (opt) { return new app(opt); }; }); })();

Answer 1

您永远不会将 window.myApp 作为函数调用，而现在您只是在声明它。 改为以下，

 (function () { console.log('loaded here'); function ready(callbackFunction){ if (document.readyState != 'loading') callbackFunction(event) else document.addEventListener("DOMContentLoaded", callbackFunction) } var app = function (options) { var app = this, version = 1.00; app.init = function () { console.log('not loaded here'); } app.init(); }; ready(event => { console.log('dom is loaded'); var opt = {}; window.myApp = new app(opt); }); })();