Mysql 数据库：加入 sums 和 group by

Question

我有两个表 OrderUpdate 和 DailyProduction

订单_更新

itemid  packages    ordercode
1       10          ORANGE
2       20          ORANGE
3       40          ORANGE
1       25          APPLE
2       50          APPLE
3       100         APPLE

每日生产

date    itemid  packages    ordercode
28-Sep  1       5           ORANGE
20-Sep  1       2           ORANGE
1-Sep   3       4           ORANGE
1-Sep   1       5           APPLE
15-Sep  2       5           APPLE
30-Sep  3       1           APPLE

结果我想跟随

itemid  packages    ordercode   ready   remaining
1       10          ORANGE      7       3
2       20          ORANGE      0       20
3       40          ORANGE      4       36
1       25          APPLE       5       20
2       50          APPLE       5       45
3       100         APPLE       1       99

Answer 1

如果我正确地跟随您，您可以使用聚合查询left join表order_update ，该查询汇总表order_update中每个(itemid, ordercode)的daily_production ：

select ou.*, coalesce(dp.ready, 0), ou.packages - coalesce(dp.ready, 0) reamining 
from order_update ou
left join (
    select itemid, ordercode, sum(packages) ready 
    from daily_production 
    group by itemid, ordercode
) dp on dp.itemid = ou.itemid and dp.ordercode = ou.ordercode