繁体   English   中英

使用各种分隔符将地址拆分为街道地址、城市、州、邮编和国家

[英]Splitting address with various delimiters into street address, city, state, zip and country

我的数据在 Excel 中。 我有几张数据,其中地址总是在每张纸的同一列中。 地址格式的示例包括:

1155 15th Street NW Suite 600 Washington, DC 20005 US
4600 Emperor Blvd #200 Durham, NC 27703-8577 美国
200 Stevens Drive 费城, PA 19113 美国
505 City Parkway West Orange, CA 92868 US
550 S Caldwell St, Charlotte, NC 28202-2633 US
1643 NW 136th Ave Ste H200 Sunrise, FL 33323-2857 美国

我已经尝试了下面的代码,但在代码“sCity = Trim(Mid$(rCell.Value, Len(sAddress) + 1, lStatePos - Len(sAddress) - 1))”中出现错误

谁能帮我弄清楚如何解决这个问题?

Sub SplitAddresses()

    Dim vaStates As Variant
    Dim vaStreets As Variant
    Dim i As Long
    Dim rCell As Range
    Dim sAddress As String
    Dim sCity As String, sState As String
    Dim sZip As String
    Dim lStreetPos As Long, lStatePos As Long

    vaStates = Array(“ AL “, “ AK “, “ AZ “, “ AR “, “ CA “, “ CO “, “ CT “, “ DE “, “ DC “, “ FL “, “ GA “, “ HI “, “ ID “, “ IL “, “ IN “, “ IA “, “ KS “, “ KY “, “ LA “, “ ME “, “ MD “, “ MA “, “ MI “, “ MN “, “ MS “, “ MO “, “ MT “, “ NE “, “ NV “, “ NH “, “ NJ “, “ NM “, “ NY “, “ NC “, “ ND “, “ OH “, “ OK “, “ OR “, “ PA “, “ RI “, “ SC “, “ SD “, “ TN “, “ TX “, “ UT “, “ VT “, “ VA “, “ WA “, “ WV “, “ WI “, “ WY “, “ GU “, “ PR “)
    vaStreets = Array(" CR ", " BLVD ", " RD ", " ST ", " AVE ", " CT ")

    For Each rCell In Sheet1.Range("A1:A5").Cells
        sAddress = "": sCity = "": sZip = "": sState = ""
        For i = LBound(vaStreets) To UBound(vaStreets)
            lStreetPos = InStr(1, rCell.Value, vaStreets(i))
            If lStreetPos > 0 Then
                sAddress = Trim(Left$(rCell.Value, lStreetPos + Len(vaStreets(i)) - 1))
                Exit For
            End If
        Next i

        For i = LBound(vaStates) To UBound(vaStates)
            lStatePos = InStr(1, rCell.Value, vaStates(i))
            If lStatePos > 0 Then
                sCity = Trim(Mid$(rCell.Value, Len(sAddress) + 1, lStatePos - Len(sAddress) - 1))
                sState = Trim(Mid$(rCell.Value, lStatePos + 1, Len(vaStates(i)) - 1))
                sZip = Trim(Mid$(rCell.Value, lStatePos + Len(vaStates(i)), Len(rCell.Value)))
                Exit For
            End If
        Next i

        rCell.Offset(0, 1).Value = "'" & sAddress
        rCell.Offset(0, 2).Value = "'" & sCity
        rCell.Offset(0, 3).Value = "'" & sState
        rCell.Offset(0, 4).Value = "'" & sZip

    Next rCell

End Sub

这是我得到的错误: error_image

您的拆分逻辑中存在一些不一致的地方,这还不包括您还必须将大写街道数组与Ucase()字符串值进行比较。

然而,好消息是 - 由于您似乎应用了后续地址逻辑,即分组城市、州 + 压缩最后一个冒号分隔符,您可以尝试以下代码:

Option Explicit             ' declaration head of code module
Enum c                      ' define column constants
    [_Start] = 0
    add1
    City
    State
    Zip
End Enum

Sub SplitAddresses()
With Sheet1
    'define dataset
    Dim lastRow As Long: lastRow = .Range("A" & .Rows.Count).End(xlUp).Row
    Dim rng As Range: Set rng = .Range("A2:A" & lastRow)
    'assign to variant datafield array (provide for 4 columns: Add+City+State+ZIP)
    Dim v: v = rng.Resize(columnsize:=4).Value2
    'split data
    doSplit v
    'write split results to any target, e.g. B:B
    .Range("B2").Resize(UBound(v), 4) = v
End With
End Sub

帮助程序doSplit

Sub doSplit(data)
Dim i As Long
For i = LBound(data) To UBound(data)
    Dim curAddress As String: curAddress = data(i, c.add1)
    
    Dim tokens, tmp
    tokens = Split(curAddress, ",")
    
    '~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
    'a) analyze string part after last ","
    '~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
    tmp = Split(Trim(tokens(UBound(tokens))) & " ", " ", 2)
    'aa) add State + Zip (to columns 3..4)
    data(i, c.State) = tmp(0): data(i, c.Zip) = tmp(1)
    
    '~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
    'b) analyze first string part
    '~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
    tmp = Split(tokens(UBound(tokens) - 1), " ")
    'data(i, c.City) = tmp(UBound(tmp))   '<< only for 1-word city names
     data(i, c.City) = getCity(tmp)       '<< see edit below
    'bb) add City + Address
    data(i, c.add1) = Split(curAddress, data(i, c.City), 2)(0)
    data(i, c.add1) = Replace(data(i, c.add1), ",", "")
Next i
End Sub

帮助功能// 由于@RonRosenfeld 的评论而进行编辑

由于会有由复合词组成的城市名称,因此上述 sub 中的城市字符串分配必须从data(r, c.City) = tmp(UBound(tmp))更改为

    data(r, c.City) = getCity(tmp)  ' << function call

函数getCity()

包括检查common第一部分为“北”、“西”或“新”,以避免至少检查包含复合城市名称的详尽列表。 所有其他需要的多于一个词的城市名称必须在额外的列表cities定义:

Function getCity(tmp) As String
'Purp.: return valid city names of either one or two parts
'[1]Definitions
    'a) List common first parts of city names like "West" in "West Orange"
        Dim common$: common = "North,West,South,East,Grand,New"
    'b) List all other needed cities consisting of compound words
        Dim cities$: cities = "Sterling Heights,Ann Arbor"
'[2]Get potential city name
    'a) Define tmp indices of potential city tokens
        Dim first&: first = UBound(tmp) - 1
        Dim secnd&: secnd = UBound(tmp)
    'b) Build city name as compound string of tmp tokens
        Dim City As String
        City = Trim(IIf(first < 0, "", tmp(first) & " ") & tmp(secnd))
'[3]Check common first parts plus additional cities list
    'a) Check for common name parts like e.g. "West" in "West Orange"
        If InStr(common & ",", tmp(first) & ",") Then getCity = City: Exit Function
    'b) Check rest in listed cities and return function result
        getCity = IIf(InStr(cities, City) > 0, City, tmp(secnd))
End Function

包括 2 个字的城市名称

根据您的评论,有一个返回字符来描述城市的街道地址,以及地址的常规格式: street|City, State Zip Country算法变得更加简单,因为一系列Split函数可以将地址部分分开。

我还使用了Type语句——不是必需的,但使代码更清晰,IMO。 根据格式的不同,某些Trim语句可能不是必需的,但它们不会受到影响。

请注意,您可以更改数据源和结果位置的范围/工作表以满足您的特定要求。

编辑:我刚刚读到您的评论,在从街道地址返回城市之前可能会有多次returns

.street代码.street更改

Option Explicit
Type Address
    street As String
    city As String
    state As String
    zip As String
    country As String
End Type
Sub splitAddresses()
    Dim wsSrc As Worksheet, wsRes As Worksheet, rRes As Range
    Dim vSrc As Variant, vRes As Variant
    Dim myAdr As Address
    Dim v, w, x, y
    Dim I As Long
    
Set wsSrc = Worksheets("sheet1")

'read into vba array for faster processing
With wsSrc
    vSrc = .Range(.Cells(2, 1), .Cells(.Rows.Count, 1).End(xlUp))
End With

Set wsRes = Worksheets("Sheet1")
    Set rRes = wsRes.Cells(1, 3)


ReDim vRes(0 To UBound(vSrc), 1 To 5)

'Headers
    vRes(0, 1) = "Street"
    vRes(0, 2) = "City"
    vRes(0, 3) = "State"
    vRes(0, 4) = "Zip"
    vRes(0, 5) = "Country"
    
For I = 1 To UBound(vSrc)
    v = Split(vSrc(I, 1), vbLf)
    With myAdr
        y = v
        ReDim Preserve y(UBound(y) - 1)
        .street = WorksheetFunction.Trim(Join(y, " "))

    w = Split(Trim(v(UBound(v))), ",")
        .city = w(0)
    
    x = Split(Trim(w(1)))
        .state = Trim(x(0))
        .zip = Trim(x(1))
        .country = Trim(x(2))
    
    vRes(I, 1) = .street
    vRes(I, 2) = .city
    vRes(I, 3) = .state
    vRes(I, 4) = .zip
    vRes(I, 5) = .country
End With

Set rRes = rRes.Resize(rowsize:=UBound(vRes, 1) + 1, columnsize:=UBound(vRes, 2))
With rRes
    .EntireColumn.Clear
    .Value = vRes
    .Rows(1).Font.Bold = True
    .Columns(4).NumberFormat = "@"
    .EntireColumn.AutoFit
End With
    
Next I

End Sub

在此处输入图片说明

暂无
暂无

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM