[英]How do I solve this cmath compiler error?
我对编码相当陌生。 我正在做一个带有函数调用的项目,我的 POW() 和 SQRT() 函数说它们没有在这个范围内声明。 我不是特别确定如何解决这个编译器错误并感谢任何反馈
#include <iostream>
#include <iomanip>
#include <cmath>
#include <cstdlib>
using namespace std;
double average(double a,double b, double c, double d);
void stdev(double a, double b, double c, double d);
int main(){
double num1,num2,num3,num4;
char repeat;
do{
cout << "Enter four decimal numbers: ";
cin >> num1 >> num2 >> num3 >> num4;
average(num1, num2, num3, num4);
stdev(num1,num2,num3,num4);
cout << "Please enter y to continue: ";
cin >> repeat;
cout << endl;
}
while (repeat == 'y');
return 0;
}
double average(double a, double b, double c, double d){
double ave;
ave = (a+b+c+d)/4;
return ave;
}
void stdev(double a, double b, double c, double d, double average){
double std, ave;
std = SQRT(POW(a-ave,2)+POW(b-ave,2)+POW(c-ave,2)+POW(d-ave,2));
cout << "The average = "<< ave << endl;
cout << "The standard deviation of these numbers = "<<std<<endl;
return;
}
sqrt 和 pow 必须是小写的,并且您还错过了 stdev 函数定义的平均值。 https://www.cplusplus.com/reference/cmath/
#include <iostream>
#include <iomanip>
#include <cmath>
#include <cstdlib>
using namespace std;
double average(double a, double b, double c, double d);
void stdev(double a, double b, double c, double d, double average);
int main() {
double num1, num2, num3, num4;
char repeat;
do {
cout << "Enter four decimal numbers: ";
cin >> num1 >> num2 >> num3 >> num4;
double avg = average(num1, num2, num3, num4);
stdev(num1, num2, num3, num4, avg);
cout << "Please enter y to continue: ";
cin >> repeat;
cout << endl;
} while (repeat == 'y');
return 0;
}
double average(double a, double b, double c, double d) {
double ave;
ave = (a + b + c + d) / 4;
return ave;
}
void stdev(double a, double b, double c, double d, double average) {
double std = sqrt(pow(a - average, 2) + pow(b - average, 2) + pow(c - average, 2) + pow(d - average, 2));
cout << "The average = " << average << endl;
cout << "The standard deviation of these numbers = " << std << endl;
return;
}
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