将多个对象数组 javascript 与值进行比较

Question

let a = [{
    isMatched: false,
    value: 'red'
}, {
    isMatched: false,
    value: 'green'
}];
let b = [{
    isMatched: false,
    value: 'red'
}, {
    isMatched: false,
    value: 'brown'
}];
let c = [{
    isMatched: false,
    value: 'white'
}, {
    isMatched: false,
    value: 'green'
}];
let d = [{
    isMatched: false,
    value: 'red'
}, {
    isMatched: false,
    value: 'orange'
}];

// 预期输出

let a = [{
    isMatched: true,
    value: 'red'
} {
    isMatched: true,
    value: 'green'
}];
let b = [{
    isMatched: true,
    value: 'red'
}, {
    isMatched: false,
    value: 'brown'
}];
let c = [{
    isMatched: false,
    value: 'white'
}, {
    isMatched: true,
    value: 'green'
}];
let d = [{
    isMatched: true,
    value: 'red'
}, {
    isMatched: false,
    value: 'orange'
}];

Answer 1

您可以使用Map ，检查地图是否包含以value作为键的数据集，如果没有，则将对象添加到地图或将存储对象的isMatched属性设置为true ，以及实际对象。

为了防止将true设置为太多，该值更改为undefined 。

 let a = [{ isMatched: false, value: 'red' }, { isMatched: false, value: 'green' }], b = [{ isMatched: false, value: 'red' }, { isMatched: false, value: 'brown' }], c = [{ isMatched: false, value: 'white' }, { isMatched: false, value: 'green' }], d = [{ isMatched: false, value: 'red' }, { isMatched: false, value: 'orange' }]; [a, b, c, d].forEach((m => a => a.forEach(o => { if (m.has(o.value)) { o.isMatched = true; const temp = m.get(o.value); if (temp) { temp.isMatched = true; m.set(o.value, undefined); } } else { m.set(o.value, o); } }))(new Map)); console.log(a); console.log(b); console.log(c); console.log(d);

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Answer 2

您可以将所有数组合二为一，然后计算出现多于 1 的值：

let combinedArrays = a.concat(b, c, d);
countValues = {}

combinedArrays.forEach(function(v) {
  if (isNaN(countValues[v.value])) {
    countValues[v.value] = 1;
  }else {
    countValues[v.value] += 1;
  }
})

然后您可以遍历每个数组并检查if countValues[value] > 1然后将isMatched设置为true