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[英]How do I edit the ResponseEntity of a Get-Request in Java Spring?
[英]How to get OpenApi Generator for Spring Java server generate ResponseEntity<Object> for PUT request?
我正在使用 openapi-generator-maven-plugin 的 4.3.1 版本在 Java 11 中生成 SpringBoot 服务器。
对于 PUT 请求,我希望能够在成功时将 URI 返回到创建/更新的对象,并在不成功时返回带有问题信息的纯文本。
我的 API json 对于 PUT 请求具有以下内容:
"put": {
"summary": "Create or update a Service",
"deprecated": false,
"operationId": "putIndividualServiceUsingPUT",
"responses": {
"200": {
"description": "Service updated"
},
"201": {
"description": "Service created",
"content": {
"text/plain": {
"schema": {
"type": "string",
"example": "services/DroneIdentifier"
}
}
}
},
"400": {
"description": "Provided service is not correct",
"content": {
"text/plain": {
"schema": {
"type": "string",
"example": "Service is missing required property version"
}
}
}
},
"401": {
"description": "Unauthorized"
},
"403": {
"description": "Forbidden"
}
},
"parameters": [
{
"name": "serviceName",
"in": "path",
"required": true,
"schema": {
"type": "string"
},
"example": "DroneIdentifier"
}
],
"requestBody": {
"description": "Service to create/update",
"required": true,
"content": {
"application/json": {
"schema": {
"$ref": "#/components/schemas/service"
}
}
}
}
生成的API:
/**
* PUT /services/{serviceName} : Create or update a Service
*
* @param serviceName (required)
* @param service Service to create/update (required)
* @return Service updated (status code 200)
* or Service created (status code 201)
* or Provided service is not correct (status code 400)
* or Unauthorized (status code 401)
* or Forbidden (status code 403)
*/
@ApiOperation(value = "Create or update a Service", nickname = "putIndividualServiceUsingPUT", notes = "", tags={ "rAPP Catalogue API", })
@ApiResponses(value = {
@ApiResponse(code = 200, message = "Service updated"),
@ApiResponse(code = 201, message = "Service created", response = String.class),
@ApiResponse(code = 400, message = "Provided service is not correct", response = String.class),
@ApiResponse(code = 401, message = "Unauthorized"),
@ApiResponse(code = 403, message = "Forbidden") })
@RequestMapping(value = "/services/{serviceName}",
produces = { "text/plain" },
consumes = { "application/json" },
method = RequestMethod.PUT)
default ResponseEntity<Void> putIndividualServiceUsingPUT(@ApiParam(value = "",required=true) @PathVariable("serviceName") String serviceName,@ApiParam(value = "Service to create/update" ,required=true ) @Valid @RequestBody Service service) {
return getDelegate().putIndividualServiceUsingPUT(serviceName, service);
}
但是,该方法的返回类型是ResponseEntity<Void>
,这意味着我无法在响应正文中放置任何内容。
难道我做错了什么? 或者生成器是否被硬编码为不允许响应 PUT 请求的主体?
生成的代码模板以 .mustache 格式存储为资源。 但是,如果您有 Maven 或 Gradle,您可以通过创建一个具有相同名称的修改文件并添加指向该文件夹的链接来轻松覆盖它。
在您的情况下,将 api.mustache 和 methodBody.mustache 文件从https://github.com/OpenAPITools/openapi-generator/tree/master/modules/openapi-generator/src/main/resources复制到您的计算机或项目资源/Java ,并通过将Response<>
替换为URI
更改它们。
将项目<templateResourcePath>folderInYourResources</templateResourcePath>
或<templateDirectory>pathToDirectory</templateDirectory>
到您的 Maven <configuration>
,一切都应该正常工作
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